Creating a Matrix that is a manipulation of another matrix
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dpb
2015-10-6
A(:,2)=-A(:,2); % negate elements in original
or
A(:,2)=-1*A(:,2);
or
B=[A(:,1) -A(:,2}]; % new array keeping old
Any number of additional ways are possible including, of course linear algebra methods...
B=A*[1 0;0 -1];
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Joseph Cheng
2015-10-6
编辑:Joseph Cheng
2015-10-6
There are lots of ways how about element by element multiplication like:
x = magic(4)
trans = [ones(4,2) -ones(4,2)]
x.*trans
which if it gets complicated say corners and such you can build the trans matrix to whatever you want.
or by selecting the columns manually:
x(:,3:4) = -x(:,3:4)
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Julian
2015-10-6
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Joseph Cheng
2015-10-6
so the indexing is something you should spend some time to read about to fully understand but its like:
x(row,column) so you can say x(2,3) which will specifically be the element of intersection of row 2 and column 3. so to replace one element you would just specify that one element. the : marker in the examples everyone is giving is the "all" marker for all rows/columns (depending on where it is)
x(:,2) is all rows in column 2
x(2,:) is for all columns for row 2.
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