Can any one help me to fix error with imread()?

Question

Nilima 2015-10-18

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评论： Walter Roberson 2015-10-19

The code is...

imgListFile = fopen('image_class.txt', 'r');
F = zeros(6, 24); L = cell(6, 1);
tline = fgetl(imgListFile); currentLine = 1;
while ischar(tline)        
    disp(tline)
    splittedLine = regexp(tline, ',[ ]*', 'split');
      imagePath = fullfile('imgs', splittedLine{1});
      I = imread(imagePath);
      f = sfta(I, 4);
      F(currentLine, :) = f;
      % Store the image label.
      L{currentLine} = splittedLine{2};
      tline = fgetl(imgListFile);
      currentLine = currentLine + 1;
  end;  
  fclose(imgListFile);

I am getting following error...

Error using imread (line 347)
Can't open file "imgs" for reading;
you may not have read permission.
Error in classifymy (line 12)
I = imread(imagePath);

I have checked read permission, but it is there? Not able to trace where is problem? Thanks in advance

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Answer 1

Geoff Hayes 2015-10-18

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在 MATLAB Online 中打开

Nilima - it sounds like you don't have read permissions for this file (though is imgs the correct name for it?). To find out, look at the permissions for this file. If using a Linux or Unix OS, open a terminal window and go to the directory where this file is located. Type

ls -ag

to list all of the files in this directory along with their permissions. In order for you to have read permissions to this file you will need to see something like

-r--r--r--@ 1 staff 43279 15 Mar 2015 myImage.gif

The r is for read. If you don't see it for the appropriate group that you are in, then you will have to add it using chmod to change the file's permissions.

If using a Windows operating system, then you can use Explorer to open the properties of the file which you can then add the read permission to.

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Nilima 2015-10-19

Dear, Geoff Sir, Thanks for reply. I have read and write permission for this folder. Still I don't know why this error coming?

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Answer 2

Walter Roberson 2015-10-18

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At some point in the file you are encountering a line which is empty before its first comma. That is leaving you with an empty splittedLine{1} and the fullfile() is then leaving "imgs" as the directory name rather than converting it to "imgs\" or "imgs/" with no following file name.