I have tried running this code and I keep getting this following error. Attempted to access P(1,2); index out of bounds because numel(P)=1. Error in Assignment_7 (line 24) A = [P(1,1) P(1,2) P(1,3) P(1,4) P(1,5) P(1,6) P(1,7) P(1,8) FTR1 FTR2 FTR3

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Sriram Paravastu 2015-11-1

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回答： Image Analyst 2015-11-2

clear
clc
Bij = [0 33.33 0 33.33 153.8 0 0 0;
     0 0 100 0 0 0 0 0; 
     0 0 0 33.33 0 0 0 0;
    0 0 0 0 33.33 0 0 0; 
    0 0 0 0 0 50 0 0; 
    40 0 0 0 0 0 0 0;
    0 0 0 80 0 0 0 45.45;
    0 0 55.55 0 0 0 0 0];
P = [];
delta = [0 0 0 0 0 0 0 0];
x0=[50 50 50 50 50 50 0 0 0 0 0 0 0 0];
for i = 1:1:8
    for j = 1:1:8
          P = Bij(i,j);
      end
  end
A = [P(1,1) P(1,2) P(1,3) P(1,4) P(1,5) P(1,6) P(1,7) P(1,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(2,1) P(2,2) P(2,3) P(2,4) P(2,5) P(2,6) P(2,7) P(2,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(3,1) P(3,2) P(3,3) P(3,4) P(3,5) P(3,6) P(3,7) P(3,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(4,1) P(4,2) P(4,3) P(4,4) P(4,5) P(4,6) P(4,7) P(4,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(5,1) P(5,2) P(5,3) P(5,4) P(5,5) P(5,6) P(5,7) P(5,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(6,1) P(6,2) P(6,3) P(6,4) P(6,5) P(6,6) P(6,7) P(6,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(7,1) P(7,2) P(7,3) P(7,4) P(7,5) P(7,6) P(7,7) P(7,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6;
    P(8,1) P(8,2) P(8,3) P(8,4) P(8,5) P(8,6) P(8,7) P(8,8) FTR1 FTR2 FTR3 FTR4 FTR5 FTR6];
B=[0 150 0 140 380 0 0 0 300 300 300 300 300 300;
    0 0 120 0 0 0 0 0 300 300 300 300 300 300;
    0 0 0 230 0 0 0 0 300 300 300 300 300 300;
    0 0 0 0 150 0 0 0 300 300 300 300 300 300;
    0 0 0 0 0 300 0 0 300 300 300 300 300 300;
    250 0 0 0 0 0 0 0 300 300 300 300 300 300;
    0 0 0 350 0 0 340 300 300 300 300 300 300;
    0 0 240 0 0 0 0 0 300 300 300 300 300 300];
Aeq=[ 0 0 -1 -1 0 0 0 0 0 0 0 0 0 0;
    0 0 1 0.4 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 -1 0.6 0 0 0 0 0 0 0 0;
    0.5 1 0 0 0 -1 0 0 0 0 0 0 0 0;
    -1 -1 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 1 0 0 0 0 0 0 0 0 0;
    0.5 0 0 0 0 1 0 0 0 0 0 0 0 0];
Beq=Bij*delta - [0;0;0;100;-100;-80;80;0];
ub = [ 300 300 300 300 300 300 30 30 30 30 30 30 30 30];
lb = [ -300 -300 -300 -300 -300 -300 -30 -30 -30 -30 -30 -30 -30 -30];
[Solution C] = fmincon(@obj,x0,A,B,Aeq,Beq,lb,ub);
FTR = Solution(1:6)
Delta = SOlution(7:14)
C

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Answer 1

Star Strider 2015-11-1

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You did not create an array for ‘P’. It is a scalar, not an array, and is equal to Bij(8,8), the last value assigned to it in the loop.

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Answer 2

Image Analyst 2015-11-2

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Maybe instead of the for loop, you simply want to set P equal to Bij - I don't know your intent. But your loops are the same as this:

P = Bij;

If you do that, then P will be an array and have a 1,2 element. As you have it, P is just a single scalar number that gets overwritten every time though your loop.