Error using the integral function - A and B must be floating-point scalars.
3 次查看(过去 30 天)
显示 更早的评论
.
1 个评论
Star Strider
2015-11-4
The original (now deleted) post included this code:
Ginf = 4.0;
t = [0:500]
t1 = 100;
t2 = 500;
y1 = @(t) t/t1;
y2 = @(t) t/t2;
fun1 = @(y)exp(-y)./y;
Eiy1 = integral(@(t)fun1(y1(t)), 0, Inf);
Eiy2 = integral(@(t)fun1(y2(t)), 0, Inf);
E21(y1) = integral((Eiy1)./y, Inf, y1)
E21(y1) = integral((Eiy2)./y, Inf, y2)
G(t) = Ginf -[Eiy1*log(t/y1)-E21(y1)]+[Eiy2*log(t/y2)-E21(y2)]
plot(G(t), t)
采纳的回答
Adam Barber
2015-11-4
Your variables "y1" and "y2" are vectors. The command:
Eiy1 = integral(fun1, Inf, y1)
is really doing the integral of : exp(-y)/y from y = Inf to a vector.
This doesn't really make sense. The bounds (2nd and 3rd input arguments to integral) need to be scalar values.
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Operators and Elementary Operations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!