Error using the integral function - A and B must be floating-point scalars.

3 次查看(过去 30 天)
.
  1 个评论
Star Strider
Star Strider 2015-11-4
The original (now deleted) post included this code:
Ginf = 4.0;
t = [0:500]
t1 = 100;
t2 = 500;
y1 = @(t) t/t1;
y2 = @(t) t/t2;
fun1 = @(y)exp(-y)./y;
Eiy1 = integral(@(t)fun1(y1(t)), 0, Inf);
Eiy2 = integral(@(t)fun1(y2(t)), 0, Inf);
E21(y1) = integral((Eiy1)./y, Inf, y1)
E21(y1) = integral((Eiy2)./y, Inf, y2)
G(t) = Ginf -[Eiy1*log(t/y1)-E21(y1)]+[Eiy2*log(t/y2)-E21(y2)]
plot(G(t), t)

请先登录,再进行评论。

采纳的回答

Adam Barber
Adam Barber 2015-11-4
Your variables "y1" and "y2" are vectors. The command:
Eiy1 = integral(fun1, Inf, y1)
is really doing the integral of : exp(-y)/y from y = Inf to a vector.
This doesn't really make sense. The bounds (2nd and 3rd input arguments to integral) need to be scalar values.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Operators and Elementary Operations 的更多信息

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by