delete words from list based on logical statement

Question

Max 2015-11-10

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https://ww2.mathworks.cn/matlabcentral/answers/254115-delete-words-from-list-based-on-logical-statement

回答： Thorsten 2015-11-12

采纳的回答： Adam Barber

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say I have a cell array x={'abatable';'abate';'abatement';'abater';'dog';'cat';'make';'abator';'see'}

and word='abatis' letter='a'

how would I delete all words from x that do not have the letter in the respective positions of the word

For example with the letter a it appears in word abatis as the 1st letter and the 3rd letter. I would then like to delete all words from x that do not have 'a' as their 1st and 3rd positions.

I have tried this

 if ismember(letter,word)
x=letter==word % returns a 1 row vector of logical statements
%.....
end

but im stuck there what else should I try.

Thanks

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Answer 1

Adam Barber 2015-11-10

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I slightly modified Jan's answer:

List = {'abatable';'abate';'abatement';'abater';'dog';'cat'; ...
        'make';'abator';'see'}
Word = 'abatis'
C    = 'a';
pattern = (Word == C);
match   = false(1, numel(List));
for k = 1:numel(List)
  currentWord = List{k};
  lenToCheck = min(numel(pattern), numel(currentWord));
  if isequal(pattern(1:lenToCheck), currentWord(1:lenToCheck) == C)
    match(k) = true;
  end
end
List(~match) = [];

Note that I am using the smaller of the two lengths between the words. As such, "dog" and "cat" won't work, but just the word "as" would.

Of course you could modify this to make your application work.

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Max 2015-11-11

Is it possible to have this work for all words like dog and cat

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Answer 2

Jan 2015-11-10

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编辑：Jan 2015-11-12

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List = {'abatable';'abate';'abatement';'abater';'dog';'cat'; ...
        'make';'abator';'see'}
Word = 'abatis'
C    = 'a';
pattern = (Word == C);
match   = false(1, numel(List));
for k = 1:numel(List)
  if isequal(pattern, (List{k} == C))
    match(k) = true;
  end
end
List(match) = [];

[EDITED, consider word with different lengths:]

...
pattern = strfind(Word, C);
match   = false(1, numel(List));
for k = 1:numel(List)
  match(k) = isequal(pattern, strfind(List{k}, C))
end
List(match) = [];

In addition I've replaced the IF branching by a direct assignment.

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Max 2015-11-10

When I type that in it returns List={'abatable';'abate';'abatement';'dog';'cat';'make';'see'}

Jan 2015-11-12

@Max: Correct, the code considers words of the same length only. See EDITED.

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Answer 3

Thorsten 2015-11-12

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Another way would be to use strvcat

List = {'abatable';'abate';'abatement';'abater';'dog';'cat'; ...
        'make';'abator';'see'}
Word = 'abatis'
C    = 'a';
pattern = (Word == C);
L = strvcat(List) == 'a'; n = size(L, 2);
if length(pattern) < n, pattern(n) = 0; end
P = repmat(pattern, size(L, 1), 1);
ind = ~any(abs(P - L), 2);
List = List(ind);