delete words from list based on logical statement

Max
2015 11 10
3 个回答
回答已采纳
更新时间：2015 11 12
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0 个投票

say I have a cell array x={'abatable';'abate';'abatement';'abater';'dog';'cat';'make';'abator';'see'}
and word='abatis' letter='a'
how would I delete all words from x that do not have the letter in the respective positions of the word
For example with the letter a it appears in word abatis as the 1st letter and the 3rd letter. I would then like to delete all words from x that do not have 'a' as their 1st and 3rd positions.
I have tried this
if ismember(letter,word)
x=letter==word % returns a 1 row vector of logical statements
%.....
end
but im stuck there what else should I try.
Thanks

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 采纳的回答

Adam Barber
Adam Barber 2015-11-10

0 个投票

I slightly modified Jan's answer:
List = {'abatable';'abate';'abatement';'abater';'dog';'cat'; ...
'make';'abator';'see'}
Word = 'abatis'
C = 'a';
pattern = (Word == C);
match = false(1, numel(List));
for k = 1:numel(List)
currentWord = List{k};
lenToCheck = min(numel(pattern), numel(currentWord));
if isequal(pattern(1:lenToCheck), currentWord(1:lenToCheck) == C)
match(k) = true;
end
end
List(~match) = [];
Note that I am using the smaller of the two lengths between the words. As such, "dog" and "cat" won't work, but just the word "as" would.
Of course you could modify this to make your application work.

更多回答（2 个）

Jan
Jan 2015-11-10
编辑：Jan 2015-11-12

1 个投票

List = {'abatable';'abate';'abatement';'abater';'dog';'cat'; ...
'make';'abator';'see'}
Word = 'abatis'
C = 'a';
pattern = (Word == C);
match = false(1, numel(List));
for k = 1:numel(List)
if isequal(pattern, (List{k} == C))
match(k) = true;
end
end
List(match) = [];
[EDITED, consider word with different lengths:]
...
pattern = strfind(Word, C);
match = false(1, numel(List));
for k = 1:numel(List)
match(k) = isequal(pattern, strfind(List{k}, C))
end
List(match) = [];
In addition I've replaced the IF branching by a direct assignment.

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Max
Max 2015-11-10
When I type that in it returns List={'abatable';'abate';'abatement';'dog';'cat';'make';'see'}
Jan
Jan 2015-11-12
@Max: Correct, the code considers words of the same length only. See EDITED.

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Thorsten
Thorsten 2015-11-12

0 个投票

Another way would be to use strvcat
List = {'abatable';'abate';'abatement';'abater';'dog';'cat'; ...
'make';'abator';'see'}
Word = 'abatis'
C = 'a';
pattern = (Word == C);
L = strvcat(List) == 'a'; n = size(L, 2);
if length(pattern) < n, pattern(n) = 0; end
P = repmat(pattern, size(L, 1), 1);
ind = ~any(abs(P - L), 2);
List = List(ind);

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