finding values in a column
显示 更早的评论
If I have a 2x6 table
x=[2.85952761913254,-1.33764402056949,-2.74861220460403,-2.39401291954310,-2.41122090675109,-2.58624072856484;1.98331894606493,2.70742364289862,3.50139737348142,3.34125579107176,3.92698601521501,0.804096918943113]
how do I find the angle that is above the highest length in the bottom. for example lengths are displayed on the second row and angles on the first. How do I find the angle in the first row for the highest length in the second row. So in this example the highest length is 3.9270 and its corresponding angle is -2.4112 so ans=-2.4112
Thanks
2 个评论
Jan
2015-11-15
This does not look like a "table", but like a standard matrix.
James Connor
2015-11-15
采纳的回答
Jan
2015-11-15
x = [2.85952761913254,-1.33764402056949,-2.74861220460403,-2.39401291954310, ...
-2.41122090675109,-2.58624072856484; ...
1.98331894606493,2.70742364289862,3.50139737348142,3.34125579107176, ...
3.92698601521501,0.804096918943113];
[maxValue, maxIndex] = max(x(2, :));
maxAngle = x(1, maxIndex);
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 MATLAB 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
