finding values in a column

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James Connor
James Connor 2015-11-15
评论： James Connor 2015-11-15
If I have a 2x6 table
x=[2.85952761913254,-1.33764402056949,-2.74861220460403,-2.39401291954310,-2.41122090675109,-2.58624072856484;1.98331894606493,2.70742364289862,3.50139737348142,3.34125579107176,3.92698601521501,0.804096918943113]
how do I find the angle that is above the highest length in the bottom. for example lengths are displayed on the second row and angles on the first. How do I find the angle in the first row for the highest length in the second row. So in this example the highest length is 3.9270 and its corresponding angle is -2.4112 so ans=-2.4112
Thanks
  2 个评论
Jan
Jan 2015-11-15
This does not look like a "table", but like a standard matrix.
James Connor
James Connor 2015-11-15
yes sorry it appears to be a matrix

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采纳的回答

Jan
Jan 2015-11-15
x = [2.85952761913254,-1.33764402056949,-2.74861220460403,-2.39401291954310, ...
-2.41122090675109,-2.58624072856484; ...
1.98331894606493,2.70742364289862,3.50139737348142,3.34125579107176, ...
3.92698601521501,0.804096918943113];
[maxValue, maxIndex] = max(x(2, :));
maxAngle = x(1, maxIndex);

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