Creating an array of structs and using the field directly?
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Hey guys. I'm wondering if there is a workaround for doing something like this:
a = {[struct('field',1) struct('field',2)].field}
which works in octave but not in matlab ("invalid syntax at '.'. Possibly a ')', ']' or '}' is missing"), I have to use a temporary variable. This is quite annoying. Is there a workaround?
Thanks!
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Stephen23
2015-11-19
编辑:Stephen23
2015-11-19
It is not clear why you need to structure at all, as the output is simply a cell array with some numeric scalars in it (Octave code below)
>> {[struct('field',1) struct('field',2)].field}
ans =
{
[1,1] = 1
[1,2] = 2
}
>> {struct('field',{1,2}).field}
ans =
{
[1,1] = 1
[1,2] = 2
}
>> {1,2}
ans =
{
[1,1] = 1
[1,2] = 2
}
If the input is already a structure, then you can simply access the field values using the methods given in the documentation for non-scalar structures:
{X.field}
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更多回答(1 个)
Jan
2015-11-19
As long as you insist on using standard struct : No, there is no workaround. Using a temporary variable is not a big deal and does not waste additional resources.
You can create your own object class, which solves the problem. But this will be less efficient.
3 个评论
Jan
2015-11-23
You can accept one answer only. But you can vote for more answers and a comment is useful also.
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