Sorting a cell array of strings on dim

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Noushin Farnoud
Noushin Farnoud 2015-12-15
编辑： per isakson 2015-12-18
Hello All,
Is there a way I can sort along the 2nd dim of a cell array of strings? When I apply sort(x,2) on the example below, I receive the error msg: DIM and MODE arguments not supported for cell arrays.
I have:
x={'book','apple';'dood','tood';'soon','moon'}
x =
'book' 'apple'
'dood' 'tood'
'soon' 'moon'
I want to sort it on 2nd dim, so that I get:
sorted_x=
'apple' 'book'
'dood' 'tood'
'moon' 'soon'
I greatly appreciate your response.
Noushin

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采纳的回答

Guillaume
Guillaume 2015-12-17
Transpose the cell array, sort, and transpose back:
x = {'book','apple';'dood','tood';'soon','moon'};
sorted_x = sort(x')'
  2 个评论
Guillaume
Guillaume 2015-12-17
A generic version of this:
function sorted_c = sort_cell(c, dim)
%c: an Nd cell array
%dim: dimension to sort
permdims = 1:ndims(c);
permdims([1 dim]) = permdims([dim 1]);
sorted_c = permute(sort(permute(c, permdims)), permdims);
end

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更多回答（1 个）

per isakson
per isakson 2015-12-15
编辑：per isakson 2015-12-18
2015-12-18: Fixed a "typo". With R2013a.
Loop over all rows and concatenate
cac = arrayfun( @(jj) sort(x(jj,:)), (1:size(x,1)), 'uni', false )
sorted_x = cat( 1, cac{:} )
outputs
cac =
{1x2 cell} {1x2 cell} {1x2 cell}
sorted_x =
'apple' 'book'
'dood' 'tood'
'moon' 'soon'

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