How can I concatenate arrays in loop ?
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Dear Contributers,
There is a loop;
for i = 1:n;
X_rotate = X.*cos(i*increment) - Y.*sin(i*increment);
Y_rotate = X.*sin(i*increment) + Y.*cos(i*increment);
Helix = [X_rotate(1:K1) ; Y_rotate(1:K1)];
fileID = fopen('helix_values.txt', 'w');
fprintf(fileID,'%f %f\n ', Helix);
fclose(fileID);
end
When open the text file, there just exists the last values of iteration X_rotate and Y_rotate. I need to collect the values for every iteration. I have tried to use cat command but I probably made mistake. How may I do that?
Thanks in advance.
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Guillaume
2015-12-22
It looks like your X and Y are row vectors of size [1, K1] (inferred from the line Helix = [X_rotate(1:K1) ; Y_rotate(1:K1)];). In that case you don't need to use a loop to calculate your X_rotate and Y_rotate:
steps = 1:n;
X_rotate = bsxfun(@times, X, cos(steps*increment)') - bsxfun(@times, Y, sin(steps*increments)');
Y_rotate = bsxfun(@times, X, sin(steps*increment)') + bsxfun(@times, Y, cos(steps*increments)');
%rows of X_rotate and Y_rotate correspond to steps
%columns correspond to the original X and Y values
I'm unclear how you want to save all the iterations onto the same text file though, columns of X and Y multiplied by the number of iterations?
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Star Strider
2015-12-22
I’m not certain what you’re doing, but to get the ‘X_rotate’ and ‘Y_rotate’ as vectors, you have to save them as such:
for i = 1:n;
X_rotate(i) = X.*cos(i*increment) - Y.*sin(i*increment);
Y_rotate(i) = X.*sin(i*increment) + Y.*cos(i*increment);
end
I don’t know what their actual dimensions are, so you might have to add a second dimension to each:
for i = 1:n;
X_rotate(i,:) = X.*cos(i*increment) - Y.*sin(i*increment);
Y_rotate(i,:) = X.*sin(i*increment) + Y.*cos(i*increment);
end
Do the file write after the loop, not in it.
5 个评论
Star Strider
2015-12-22
I am not certain how your program is organised. However a while loop with a counter, or some other way to determine the size of the user’s inputs, for example asking the user, would be useful to define ‘n’.
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