How do I convert a cell array to matrix whose dimensions are not equal?

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mydata =
[195x1 double] [124x1 double] [1826x1 double] [2x1826 double] [195x124x1826 single]
  5 个评论
Jan
Jan 2016-2-11
I neither understand the meanig of the images, not the description "matrix form with different file names".
Geoff Hayes
Geoff Hayes 2016-2-11
Manoj - how should all of this data, from your cell array, be packaged into the matrix? What should the dimensions be for the matrix?

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Walter Roberson
Walter Roberson 2016-2-11
%using variable names from your posting, structure as in capture.JPG
md1 = mydata{1};
md2 = mydata{2};
md3 = mydata{3};
md4 = mydata{4};
md5 = mydata{5};
[X, Y, Z] = ndgrid(md1, md2, md3);
pointsize = 20;
scatter3(X(:), Y(:), Z(:), pointsize, md5(:));
%using variable names from data file.JPG
%the data is a mix of int16 and int32 and we need to make it all the same datatype to
%make it into a numeric matrix without risk that the wrong datatype would be used
temp = cellfun(@(M) int32(M.'), permute(B,[1 3 2]), 'Uniform', 0);
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
The result of this, B30, would be a 30 x 10666 numeric array, in which each row is formed by concatenating together the 2446 x 1, 2532 x 1, 2651 x 1, 3037 x 1 as one piece and making that a row.
  3 个评论
Manoj
Manoj 2016-2-15
编辑:Walter Roberson 2016-2-15
2)
md = mydata{1};
md1 = mydata{2};
[X Y]=ndgrid(md,md1);
temp = cellfun(@(M) int32(M.'), permute(B,[1 3 2]), 'Uniform', 0);
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
Error using arrayfun
All of the input arguments must be of the same size and shape.
Previous inputs had size 7 in dimension 2. Input #3 has size 1
Walter Roberson
Walter Roberson 2016-2-15
You have changed the size of your data in mydata. Please show the current summary of mydata and also of B.
The line
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
should be
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 1:size(temp,1), 'Uniform', 0) );

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