How do I convert a cell array to matrix whose dimensions are not equal?

2016 2 10
1 个回答
回答已采纳
更新时间：2016 2 15
3 次查看（30 天）

0 个投票

mydata =
[195x1 double] [124x1 double] [1826x1 double] [2x1826 double] [195x124x1826 single]

5 个评论
显示 3更早的评论 隐藏 3更早的评论

Geoff Hayes
Geoff Hayes 2016-2-10
Manoj - are you trying to convert the above to a matrix using cell2mat? If so, what are the dimensions of the matrix that you are trying to obtain? Please show the code that you have written that generates the error.
Manoj
Manoj 2016-2-11
Geoff Hayes
Pls find the attachment of the .jpg images having the cell array of B consists the data of different dimensions. I need to convert the cell array in to matrix form with different file names, so that I can choose the data for plotting.
Thanks
Manoj Kumar
Jan
Jan 2016-2-11
I neither understand the meanig of the images, not the description "matrix form with different file names".
Geoff Hayes
Geoff Hayes 2016-2-11
Manoj - how should all of this data, from your cell array, be packaged into the matrix? What should the dimensions be for the matrix?

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Walter Roberson
Walter Roberson 2016-2-11

2 个投票

%using variable names from your posting, structure as in capture.JPG
md1 = mydata{1};
md2 = mydata{2};
md3 = mydata{3};
md4 = mydata{4};
md5 = mydata{5};
[X, Y, Z] = ndgrid(md1, md2, md3);
pointsize = 20;
scatter3(X(:), Y(:), Z(:), pointsize, md5(:));
%using variable names from data file.JPG
%the data is a mix of int16 and int32 and we need to make it all the same datatype to
%make it into a numeric matrix without risk that the wrong datatype would be used
temp = cellfun(@(M) int32(M.'), permute(B,[1 3 2]), 'Uniform', 0);
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
The result of this, B30, would be a 30 x 10666 numeric array, in which each row is formed by concatenating together the 2446 x 1, 2532 x 1, 2651 x 1, 3037 x 1 as one piece and making that a row.

3 个评论
显示 1更早的评论 隐藏 1更早的评论

Manoj
Manoj 2016-2-15
编辑：Walter Roberson 2016-2-15
Thank you for your reply
but I am getting two errors after running the below code.
1)
md = mydata{1};
md1 = mydata{2};
md2 = mydata{3};
[X Y Z]=ndgrid(md,md1,md2);
temp = cellfun(@(M) int32(M.'), permute(B,[1 3 2]), 'Uniform', 0);
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
Error using repmat
Requested 5949x5949x5949 (1568.6GB) array exceeds maximum array size preference. Creation of arrays greater than this
limit may take a long time and cause MATLAB to become unresponsive. See array size limit or preference panel for more
information.
Error in ndgrid (line 73)
varargout{i} = repmat(x,s);
Manoj
Manoj 2016-2-15
编辑：Walter Roberson 2016-2-15
2)
md = mydata{1};
md1 = mydata{2};
[X Y]=ndgrid(md,md1);
temp = cellfun(@(M) int32(M.'), permute(B,[1 3 2]), 'Uniform', 0);
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
Error using arrayfun
All of the input arguments must be of the same size and shape.
Previous inputs had size 7 in dimension 2. Input #3 has size 1
Walter Roberson
Walter Roberson 2016-2-15
You have changed the size of your data in mydata. Please show the current summary of mydata and also of B.
The line
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
should be
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 1:size(temp,1), 'Uniform', 0) );

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Data Type Conversion 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by