Info

此问题已关闭。 请重新打开它进行编辑或回答。

How can I join both the initial and final values of a function (lineal, curve..) and the vertical axis x = 0, either for positive or negative values of it?

1 次查看(过去 30 天)
I have several diagrams which plot one function. I want to join both the initial and final values of a function (lineal, curve..) and the vertical axis x = 0, either for positive or negative values of it.
In other words, it is like closing the function respect to the vertical axis x=0. The function is a piecewise function. The code of one case is:
y_B1 = 0:0.01:h_poste;
Mz_B1 = -((y_B1<=h_hc).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1))+((y_B1>h_hc)&(y_B1<=h_CdPa)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht)))+((y_B1>h_CdPa)&(y_B1<=cdg_mensula_y)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa)))+((y_B1>cdg_mensula_y)&(y_B1<=h_sust)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa))+M_mensula)+((y_B1>h_sust)&(y_B1<=h_Feed)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa))+M_mensula+M_sust+(Esf_rad_sust+Qwc(2)).*(y_B1-(h_sust+ht)))+((y_B1>h_Feed)&(y_B1<=h_poste)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa))+M_mensula+M_sust+(Esf_rad_sust+Qwc(2)).*(y_B1-(h_sust+ht))+M_Feed+(Esf_rad_Feed_B+Qwc(4)).*(y_B1-(h_Feed))));
figure
ley_Mz_B1 = plot(Mz_B1,y_B1);grid;
title('CASO DE CARGA B (Viento 1).Ley de esfuerzos flectores')
xlabel('Momento flector Mz (N·m)');
ylabel('Altura (m)');
where Mz_B1 is the function represented and y_B1 is the vector of independent values.

回答(0 个)

此问题已关闭。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by