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it is showing not enough input arguments

1 次查看(过去 30 天)
function out = g(x1 , x2)
out = x1 * x2 - 1140;
function [dGdX1 dGdX2] = dGdX(x1 , x2)
dGdX1 = x2 ;
dGdX2 = x1 ;
clc ;
clear ;
close a l l ;
format short g ;
% −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− %
mu_x1 = 38;
sigma_x1 = 3.8;
mu_x2 = 54;
sigma_x2 = 2.7;
x1 = mu_x1
x2 = mu_x2
[dg_dx1 dg_dx2] = dGdX(x1 , x2 ) ;
g_ = g(x1 , x2)
beta = g_ / sqrt (( dg_dx1 * sigma_x1)^2 + (dg_dx2 * sigma_x2)^2)
alpha_1 = -dg_dx1 * sigma_x1 / sqrt (( dg_dx1 * sigma_x1)^2 +...
(dg_dx2 * sigma_x2 )^2);
alpha_2 = -dg_dx2 * sigma_x2 / sqrt (( dg_dx1 * sigma_x1)^2 +...
(dg_dx2 * sigma_x2 )^2);
u1 = beta * alpha_1 ;
u2 = beta * alpha_2 ;
x1 = mu_x1 + u1 * sigma_x1
x2 = mu_x2 + u2 * sigma_x2
epsilon = 1.0;
while epsilon > 1E-3
g_ = g(x1 , x2)
[dg_dx1 dg_dx2] = dGdX(x1 , x2 ) ;
beta_old = beta ;
beta = (g_ - dg_dx1 * sigma_x1 * u1 - dg_dx2 * sigma_x2 * u2 )...
/ sqrt (( dg_dx1 * sigma_x1)^2 + (dg_dx2 * sigma_x2)^2)
epsilon = abs( beta - beta_old ) / beta_old
alpha_1 = -dg_dx1 * sigma_x1 / sqrt (( dg_dx1 * sigma_x1)^2 +...
(dg_dx2 * sigma_x2 )^2);
alpha_2 = -dg_dx2 * sigma_x2 / sqrt (( dg_dx1 * sigma_x1)^2 +...
(dg_dx2 * sigma_x2 )^2);
u1 = beta * alpha_1 ;
u2 = beta * alpha_2 ;
x1 = mu_x1 + u1 * sigma_x1
x2 = mu_x2 + u2 * sigma_x2
end
can any one help?
  2 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2016-4-9
What is the aim of assigning variables then clearing them?
dGdX1 = x2 ;
dGdX2 = x1 ;
clc ;
clear
Jan
Jan 2016-4-9
编辑:Jan 2016-4-9
"close a l l ;"? Do you mean "close all;" without magic spaces?
You forgot to post the complete error message. Most of all the line, which causes the error, would be a useful information.

回答(1 个)

Kuifeng
Kuifeng 2016-4-10
%Remove the following lines from the code
clc ;
clear ;
close a l l ;
  2 个评论
vaibhav mohadikar
vaibhav mohadikar 2016-4-10
Thank you but its still keep saying that not enough input arguments in line 2.
Walter Roberson
Walter Roberson 2016-4-11
And lucky for you that it did, as otherwise your code would recurse infinitely. You invoke [dg_dx1 dg_dx2] = dGdX(x1 , x2 ) ; within your dGdX code, so it would go back and start the routine all over again, and hit that line and go back and start the routine all over again, and so on.

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