standard deviation in matlab
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Hello, I have calculate in my program the mean value and I am trying to calculate the standard deviaton value of an array 20x20, without using the std command.Next, I compare my result to that whoch I get when I use the std command, but they are different.Could someone explain me the reason? Is their any problem in the types of my algorithm? Here is my code:
mean_value = 65.4250;
sum_dev = 0;
for i=1:1:20
for j=1:1:20
sum_dev = sum_dev + ((ROI(i,j)- mean_value)^2);
end;
end;
std_dev = ((sum_dev/(40-1))^(1/2));
disp(std_dev);
129.0786
std(ROI(:), 0,1)
ans =
40.3552
1 个评论
Jan
2011-3-9
Sorry for asking: Is the "mean_value" the mean of the values?!
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Teja Muppirala
2011-3-9
0 个投票
You probably meant to write (400-1) and not (40-1).
2 个评论
john
2011-3-9
Teja Muppirala
2011-3-9
It should be noted, you could have avoided this by writing something like:
std_dev = ((sum_dev/(numel(ROI)-1))^(1/2));
instead. In general, you're probably better off not hardcoding numbers like "400" (same goes for the loop indices). This is a lot more flexible since it works for any ROI size.
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