Creating Matrix with nested loop values
显示 更早的评论
Hello, I am looking for a solution with my problem storing the output of my nested loop into a matrix. The code works perfectly fine and gives me a row for every looped index. For example :
xm =
2 56 31
xm =
2 57 24.667
What i want:
All rows together in one Matrix. hours,minutes,seconds are double values format %f
zeit = [hours minutes seconds ];
houra=1;
minutea=1;
houre=1;
minutee=1;
for k=2:3
for n=1:60
houra=k-1;
minutea=n-1;
houre=k;
minutee=n;
x=(zeit(zeit(:,1)>=houra & zeit(:,1)<houre & zeit(:,2)>=minutea & zeit(:,2)<minutee ,:));
xm=mean(x);
end
end
I hope you can help me.
采纳的回答
Andrei Bobrov
2016-4-14
[a,~,c] = unique(zeit(:,1:2),'rows');
xm = [a, accumarray(c,zeit(:,3),[],@mean)];
3 个评论
Peter Krainer
2016-5-2
Andrei Bobrov
2016-5-2
Hi Peter! For zeit with size [m x 12]:
[m,n] = size(zeit);
[a,~,c] = unique(zeit(:,1:2),'rows');
[x,y] = ndgrid(c,1:n-2);
A = zeit(:,3:end);
xm = [a, accumarray([x(:),y(:)],A(:),[],@mean)];
Peter Krainer
2016-5-2
更多回答（1 个）
zeit = ???
size1 = 2 * 60;
xm = zeros(size1, 3);
ixm = 0;
for k = 2:3
hMatch = (zeit(zeit(:,1) >= ha & zeit(:,1) < he);
for n = 1:60
ha = k-1;
ma = n-1;
he = k;
me = n;
mMatch = (hMatch & zeit(:,2) >= ma & zeit(:,2) < me);
ixm = ixm + 1;
xm(ixm, :) = mean(zeit(hMatch & mMatch, :));
end
end
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