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Reshape a matrix order

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Aswas
Aswas 2016-5-16
编辑： Aswas 2016-5-16
Hi,
Vv =
1
2
3
4
5
6
7
8
9
and have transposed onto :
g =
-1 -1 -1 -1 -1 -1 -1
-1 1 3 5 0 0 8
-1 2 4 6 7 0 9
and using
Ans(zi) = reshape([Vv'], [], 1)'; to get reshaped to:
-1 -1 -1 -1 -1 -1 -1
-1 1 2 3 0 0 4
-1 5 6 7 8 0 9
but keep getting error.
  1 个评论
Jan
Jan 2016-5-16
What is your question? Which error messages do you get? Wher do the "-1" in the output come from?

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采纳的回答

Jan
Jan 2016-5-16
With some guessing:
GT = G.';
zi = find(GT == 0);
GT(zi) = Vv;
g = GT.';

更多回答（1 个）

Walter Roberson
Walter Roberson 2016-5-16
You are reshaping the row vector Vv' to be a row vector and the transposing it to a column vector, ending up back with the same Vv column vector you started from. You then try to store that entire column vector at the location Ans(zi) . If zi is not a column vector of the same length as Vv, that is going to be an error.
You should avoid using a variable named Ans as it could easily be confused with ans
  1 个评论
Jan
Jan 2016-5-16
@Aswas: Please learn hiow you use the "{} Code" button in the forum's interface. Thanks.

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