How to create 3d array equivalent to fortran dimension?

Hello all, I have this fortran code
dimension x(2,m,n)
where m=100, n=40 Now how to convert this into the matlab?

 采纳的回答

Perhaps you mean:
x = zeros(2, m, n)

2 个评论

Thank you. It does create 2XmXn array but this gives zeros of the defined size matrix
In fortran this is not the case. Please guide.
Sorry. This helped me. Thank you. Now I am facing a new issue.
My fortran code says
j=1,m
g(j) = t(k,i,j)*dcos(anglezx) - t(j)*dsin(anglezx)
How can I do this 3d multiplication in 1d in matlab. If I use this as it is I get size error for g(j) as matlab cosiders it as 1x1 while my t(k,i,j) is a 2xmxn sized matrix.

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更多回答(1 个)

this code probably is wrong the correct Fortran code would be like
do k=1,aa
do i=1,n
do j=1,m
g(j) = t(k,i,j)*dcos(anglezx) - t(j)*dsin(anglezx)
enddo
enddo
enddo
Please change to
for k=1:aa
do i=1:n
do j=1:m
g(k,j,i) = t(k,i,j)*dcos(anglezx) - t(j)*dsin(anglezx)
end
end
end

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