repacing a value by another

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kash
kash 2012-2-9
I have a matrix of 100x6 for ex let me take 6x6
[1 2 3 4 5 6
11 58 12 8 2 12
2 10 36 69 1 20
14 85 94 20 36 5
19 58 41 52 69 87
10 25 36 78 01 25]
now i want to replace the values as this,taking evry 2 elements in column wise as a pair,
for ex 1&11 must be replaced by a number 0.1
2 and 14 must be replaced by 0.2
19and 10 must be replaced by 0.3 (these for first column)
for 2nd column the values must be replaced is 2.0,2.1,2.2.....
please help
  1 个评论
Jan
Jan 2012-2-9
I do not understand the pattern. Do the new values depend on the old values, or just on the indices? Why is "19 and 10" replaced by 0.3?

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-2-9
A =rand(100,6);
[i1,j1] = ndgrid( 1:ceil(size(A,1)/2),1:size(A,2));
i1(:,2:end) = i1(:,2:end) - 1;
j1(:,1) = j1(:,1) - 1;
k=max(max(ceil(log10(i1))));
i1 = i1./10.^(k);
out = reshape(permute(repmat(i1+j1,[1,1,2]),[2 3 1]),size(A,2),[])';

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