how to Design PID controller for second order untable process

8 次查看(过去 30 天)
How a PID controller can be designed for a second order SISO process, of the form -a/S^2-b, where a,b>0 .

采纳的回答

Arkadiy Turevskiy
Arkadiy Turevskiy 2012-2-13
Not sure if that is what you are looking for, but here is how you could do it in Control System Toolbox:
>>a=1; % change to desired value
>>b=4; % change to desired value
>>s=tf('s');
>>plant=-a/(s^2-b);
>>C=pidtune(plant,'PID'); design pid controller
>>step(feedback(C*plant,1)); plot the step response of the closed-loop system
>>pidtool(plant); % open the GUI for interactive tuning
HTH. Arkadiy
  2 个评论
Harshit Gole
Harshit Gole 2012-2-19
sir ,
after entering the command
"C=pidtune(plant,'PID');"
it is showing an error
"??? Undefined function or method 'pidtune' for input arguments of type 'tf'."
please guide me.
Walter Roberson
Walter Roberson 2012-2-19
pidtune is new as of R2010b
http://www.mathworks.com/help/toolbox/control/rn/bsllzup-1.html

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 PID Controller Tuning 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by