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How to delete consecutive values in a vector and to save just the biggest one?

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Miro Mitev
Miro Mitev 2016-9-1
评论： Stephen23 2019-9-19
I have a vector like: a=[1 2 3 7 10 11 12]. The idea that i want to implement is: if I have consecutive numbers (in this situation) 1 2 3 and 10 11 12 to save just the biggest one and still to not delete the "7". So it should become: a=[3 7 12].
My code (it doesnt work properly and gives me error also):
a=[1 2 3 7 10 11 12]
k=numel(a);
for n=2:k
if a(n)==(a(n-1)+1)
a(n)=[];
end
end

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采纳的回答

Stephen23
Stephen23 2016-9-1
编辑：Stephen23 2016-9-1
If the sequences are integer and increasing only:
>> a = [1,2,3,7,10,11,12];
>> x = [diff(a)~=1,true];
>> a(x)
ans =
3 7 12
  3 个评论
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Brian
Brian 2019-9-18
If anyone comes across this and is having issues ("horzcat" error) using vertically orientied data as I was, just transpose the array inside of the diff function. For example:
>> a = [1;2;3;7;10;11;12]
>> x = [diff(a')~=1,true];
>> a(x)
ans =
3
7
12
Stephen23
Stephen23 2019-9-19
@Brian: it is simpler and more efficient to just concatenate along the first dimension:
>> x = [diff(a)~=1;true];
>> a(x)
ans =
3
7
12

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