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Find Indexes above zero in a matrix and replace thoses indexes with the value of a vector with the same length.

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Alexandros Samp
Alexandros Samp 2016-9-7
编辑： Andrei Bobrov 2016-9-7
Hello, I have matrix A=(112,20) size and a vector with V=(112,1) size. I want to find the indexes in every column in A that are above zero and replace them with the value of the vector with the same index.[x z]=find(A(:,1)>0) returns the indexes and also V(x) returns the vectors with the values i want, but i want to do this for A(:,1),A(:,2)...A(:,20) and store those values in a new Matrix B=(:,20)

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Andrei Bobrov
Andrei Bobrov 2016-9-7
编辑：Andrei Bobrov 2016-9-7
B = bsxfun(@times,A > 0,V) + A.*(A <= 0);
or
[ii,jj] = find(A > 0);
B = A;
B(sub2ind(size(A),ii,jj)) = V(ii);

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