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How to covert a cell to multiple line string?

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Sundeepan
Sundeepan 2016-9-26
编辑： Sundeepan 2016-9-26
I have a cell with one coloumn and varing number of rows. The cell contains alpha-numeric string. I want to convert this cell into a multiple line string with each cell content as one line of the string.
How can this be acheived ?
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Jan
Jan 2016-9-26
Cells are arrays. Therefore all columns have the same number of rows. I assume, the contents of the cell elements are char vectors with a different number of clumns.

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采纳的回答

Jan
Jan 2016-9-26
If you use CHAR you get a CHAR matrix padded with blanks on the right side. You can get "multi-line" also by inserting line breaks:
CellString = {'some'; 'strings'; 'to'; 'convert'; 'to'; 'a'; 'char'; 'array'}
CharString = sprintf('%s\n', CellString{:});
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Sundeepan
Sundeepan 2016-9-26
编辑：Sundeepan 2016-9-26
Thanks Guillaume & Jan for the solution. I tried out both the solutions suggested and find adding line breaks more effective.
The reason to change the cell content to multiline string was to define the model properties for a Simulink model(multiple m files).

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Guillaume
Guillaume 2016-9-26
Use char:
cellarrayofstring = {'some'; 'strings'; 'to'; 'convert'; 'to'; 'a'; 'char'; 'array'}
chararrayofstring = char(cellarrayofstring)

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