Number to string within numeric matrix

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I have numbers (1-20) which correspond to a city. I want to convert each number to a string to more easily read the city. For example: 1 = 'Atlanta', 2='Boston', etc. I have the data grouped in cell arrays based on a specific column, but also have the data in a 425x15 matrix (before grouping). Is it possible to replace the city numbers with city names? Thanks.
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Tyler Smith
Tyler Smith 2016-10-6
Thanks for all the help! I ended up using a combination of your answers. I used a categorical and turned it into a table, then turned my double into a table so I could horzcat and visualize the cities next to their respective data.

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采纳的回答

dbmn
dbmn 2016-10-6

have you tried using a categorical?

categorical([1 2 1 1 2 2], [1,2], {'Atlanta'; 'Boston'})
ans = 
     Atlanta      Boston      Atlanta      Atlanta      Boston      Boston 

更多回答(3 个)

Matthias Walle
Matthias Walle 2016-10-6
Hi,
create a new class file
classdef city < uint32
enumeration
Atlanta (1)
Boston (2)
Whatever (3)
andsoon (4)
end
end
then you can use
city(1)
for example to get Atlanta
I hope this works for you
  2 个评论
Tyler Smith
Tyler Smith 2016-10-6
When I use this, it simply returns a 1 for Atlanta, 2 for Boston, and so on (which I already have). I need it to return the names instead of the numbers. Perhaps I am using it incorrectly.
lenny006
lenny006 2016-10-7
编辑:lenny006 2016-10-7
Thank you very much. This has helped me indeed, Matthias Walle

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Steven Lord
Steven Lord 2016-10-6
You can't store both numbers and characters in a numeric array or a char array without conversion.
A = ones(2) % A is a double array
A(4) = 'A' % double('A') is 65, so A will be [1 1; 1 65]
B = 'ABCDE' % B is a char array
B(5) = 90 % char(90) is 'Z' so B will be 'ABCDZ'
You could use a cell array or a table to store data of both types.
C = {ones(5), 'abracadabra'}
x = [1; 3; 6; 10];
y = {'Amherst'; 'Boston'; 'Cambridge'; 'Easthampton'};
ind = [1 1 2 2 2 2 3 3 3 4]
D = y(ind)
E = table(x, y)

Jan
Jan 2016-10-6
You can use the city numbers as indices:
Names = {'Atlanta', 'Boston', 'Chicago'};
Data = [1, 3.14; 3, 7.07; 2, 2.71];
fprintf(%s\n', Names{Data(:, 1)})

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