zero crossing and inflection point
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can someone please in detail explain to me what this simple line of coding is doing in order to calculate zero crossing. I thought you needed the second derivative of the function to do this. Thank you
zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0);
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John D'Errico
2016-11-1
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Why would you possibly need the second derivative to locate a zero crossing?
All this does is look for consecutive elements of a vector that have different signs.
If you really want to see what it does, read the help for circshift. My re-writing existing help will be a waste of time. Given that, what property do two numbers have if they have different signs? Answer: the product will ALWAYS be negative. So all that line does is look for consecutive elements with opposite signs. (Zero will do too.)
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