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% Note :- in this code y & x has 10 values, but every time I run % the command it will give me this error... %*(??? Operands to the and && operators must be convertible to logical scalar values.)*
Error in ==> dewpointT at 75 if (abs(raw(1)) < 1e-5 && abs((y./K)-x) < 1e-5)
raw(1)= sum(y./K)-1;
if (abs(raw(1)) < 1e-5 && abs((y./K)-x) < 1e-5)
break
采纳的回答
Titus Edelhofer
2012-3-4
Hi,
if y and x are vectors, then abs((y./K)-x)<1e-5) is a (logical) vector as well. You will need to decide, if the relation must hold for at least one index, or for all of them. Replace by
any(abs((y./K)-x)<1e-5))
or
all(abs((y./K)-x)<1e-5) )
accordingly.
Titus
更多回答（1 个）
Jan
2012-3-4
0 个投票
The error message is very clear: "Operands to and && operators must be convertible to logical scalar values." It is always worth to read the error messages of Matlab.
2 个评论
Nasir Qazi
2012-3-5
Walter Roberson
2012-3-5
Nasir, it doesn't bomb out with an error if you change to &, but that doesn't mean that it works. Please review Titus's response and study the documentation for "any" and "all"
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2012-3-4
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