I have a cell (NewCell {1,1}) with 1 column and many rows, each row has or '0' or []. If its '0', I want to make a comparison; if its the other thing, i want a 'V'.

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Eduardo Rocha 2016-11-8

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编辑： Eduardo Rocha 2016-11-8

 teste2 = cell(size(catconsumo));
 for k=2:(length(Preos2013S1)-1)
     if NewCell{1,1}{k} == '0'
        mask       = strcmp(catracio1, 'low') & strcmp(catpreco, 'high');
        teste2(mask) = {'A'};
        mask       = strcmp(catracio1, 'medium low') & strcmp(catpreco, 'medium high');
        teste2(mask) = {'B'};
        mask       = strcmp(catracio1, 'medium') & strcmp(catpreco, 'medium');
        teste2(mask) = {'C'};
        mask       = strcmp(catracio1, 'medium high') & strcmp(catpreco, 'medium low');
        teste2(mask) = {'D'};
        mask       = strcmp(catracio1, 'high') & strcmp(catpreco, 'low');
        teste2(mask) = {'E'};
    elseif NewCell{1,1}{k} ~= '0'
        teste2{k}='V';
    end
 end

However, teste2 results with [] in every row, or one of those letters, but regardless of there is a [] or a '0' in NewCell{1,1}. Its not respecting the 'if' condition. Can somebody help me please?

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bemin 2016-11-8

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You need to give little more details about your cell, However What I see from your code that you are trying to compare number with a string so you ether use strcmp () or write the if without quotations just like this:-

 if NewCell{1,1}{k} ==  0
...
...
..
etc.

I hope I can help

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Answer 1

James Tursa 2016-11-8

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编辑：James Tursa 2016-11-8

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elseif isempty(NewCell{1,1}{k})

The problem you are having is that the result of NewCell{1,1}{k} ~= '0' is empty in that branch, not true, so you don't get into the elseif block.

Or, if you know for sure that there are only '0' and [] in NewCell{1,1}{k}, you could just turn that entire elseif statement into an else. E.g.,

    else
        teste2{k}='V';

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Eduardo Rocha 2016-11-8

编辑：Eduardo Rocha 2016-11-8

Actually it seemed to work, but in fact it does not. I forgot to add some information:

When NewCell(1,1){k} is '0' and none of those conditions are satisfied, teste2(k) should be '0'. When NewCell(1,1){k} is [], teste2 should be 'V'.

However, teste2 is being [] for situations in which NewCell(1,1){k} is '0' and sometimes its making the comparison when NewCell(1,1){k} is [], which can't happen.

In teste2, there should only be '0', 'A', 'B', 'C', 'D', 'E' and 'V'

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