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While loop for sums?

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Miranda Moore
Miranda Moore 2016-12-1
评论： Walter Roberson 2022-10-23
Add up the squares of all odd positive integers until it equals or exceeds 5 million.
(1^2+3^2...)
  2 个评论
Steven Lord
Steven Lord 2016-12-1
Show what you've tried to do to solve the problem and ask a specific question about where you're having difficulty and you may receive some guidance.
Rena Berman
Rena Berman 2017-1-20
(Answers Dev) Restored Question.

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回答（3 个）

Image Analyst
Image Analyst 2016-12-1
Try this:
theSum = 0; % Initialize
thisNumber = -1;
while theSum < 5000000
thisNumber = thisNumber + .......
theSum = theSum + ......
end
I've given you a start. Please finish the rest of your homework yourself.
s.p4m
s.p4m 2016-12-1
编辑：s.p4m 2016-12-2
sum=0;
k=0;
while(sum<=5*10^6)
if(mod(k,2))
sum=sum+k^2;
end
k=k+1;
end
Next time please try to solve your homework by yourself
  5 个评论
显示 3更早的评论
s.p4m
s.p4m 2016-12-2
Thanks for the answer. You are right with every point.
I didn't know about the rule not to do outher people homework, but I will embrace it from now on.
Jan
Jan 2016-12-2
编辑：Jan 2016-12-2
5. 5*10^6 is an expensive power operation, while 5e6 is cost free constant.
Thanks, s.p4m, for you suggestion. If the OP reads the comments carefully, he has learned something about programming. :-)

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prin
prin 2022-10-23
jum=100; n = 1; while sum(1:r) > jum
disp(r)
n = n - 1;
  1 个评论
Walter Roberson
Walter Roberson 2022-10-23
r is not defined. You are missing the "end" of the "while".

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