Write a single for statement to print the letters ‘A’ to ‘Z’ each 10 letters on a separate line.

28 次查看（过去 30 天）
Khalid Khan
Khalid Khan 2016-12-2
评论： Walter Roberson 2018-9-2
I am new to matlab this is my code can anyone help me
for array = [A B C D E F G H I J K L M N O P Q R S T U V W X Y Z]
count = 1:27;
if count > 10
fprintf('%s\n', array)
end
end

请先登录，再回答此问题。

回答（5 个）

Jan
Jan 2016-12-2
编辑：Jan 2016-12-5
fprintf('%c%c%c%c%c%c%c%c%c%c\n', 'A':'Z')
or:
fprintf([repmat('%c', 1, 10), '\n'], 'A':'Z')
In the 2nd version, you do not have to count manually in case of debugging or modifying the code.
Andrei Bobrov
Andrei Bobrov 2016-12-2
a = 'A':'Z';
out = reshape([a,repmat(' ',1,mod(-numel(a),10))],10,[])';
Alexandra Harkai
Alexandra Harkai 2016-12-2
count = 1;
for array = char(double('A'):double('Z')) % create character array from 'A' to 'Z'
fprintf('%s', array);
if count == 10
fprintf('\n');
count = 1; % start from the beginning of the line
else
count = count+1;
end
end
fprintf('\n');
Getinet Amare
Getinet Amare 2018-9-2
allLetters=['A' 'B' 'C' 'D' 'E' 'F' 'G' 'H' 'I' 'J' 'K' 'L' 'M' 'N' 'O' 'P' 'Q' 'R' 'S' 'T' 'U' 'V' 'W' 'X' 'Y' 'Z'];
[dim,si]=size(allLetters);
count=0;
for i = 1:1:si
%fprintf('%s \t',strcat(allLetters(i),'1'))
fprintf('%s \t',allLetters(i))
for m = 1:1:si
ai=allLetters(i);
aj=allLetters(m);
%se=strcat(ai,aj,'1');
se=strcat(ai,aj);
fprintf('%s \t',se)
count=count+1;
end
end
fprintf('Total Number of letters %s ',count)
Getinet Amare
Getinet Amare 2018-9-2
>> Excel()
output of the above source code
A AA AB AC AD AE AF AG AH AI AJ AK AL AM AN AO AP AQ AR AS AT AU AV AW AX AY AZ B BA BB BC BD BE BF BG BH BI BJ BK BL BM BN BO BP BQ BR BS BT BU BV BW BX BY BZ C CA CB CC CD CE CF CG CH CI CJ CK CL CM CN CO CP CQ CR CS CT CU CV CW CX CY CZ D DA DB DC DD DE DF DG DH DI DJ DK DL DM DN DO DP DQ DR DS DT DU DV DW DX DY DZ E EA EB EC ED EE EF EG EH EI EJ EK EL EM EN EO EP EQ ER ES ET EU EV EW EX EY EZ F FA FB FC FD FE FF FG FH FI FJ FK FL FM FN FO FP FQ FR FS FT FU FV FW FX FY FZ G GA GB GC GD GE GF GG GH GI GJ GK GL GM GN GO GP GQ GR GS GT GU GV GW GX GY GZ H HA HB HC HD HE HF HG HH HI HJ HK HL HM HN HO HP HQ HR HS HT HU HV HW HX HY HZ I IA IB IC ID IE IF IG IH II IJ IK IL IM IN IO IP IQ IR IS IT IU IV IW IX IY IZ J JA JB JC JD JE JF JG JH JI JJ JK JL JM JN JO JP JQ JR JS JT JU JV JW JX JY JZ K KA KB KC KD KE KF KG KH KI KJ KK KL KM KN KO KP KQ KR KS KT KU KV KW KX KY KZ L LA LB LC LD LE LF LG LH LI LJ LK LL LM LN LO LP LQ LR LS LT LU LV LW LX LY LZ M MA MB MC MD ME MF MG MH MI MJ MK ML MM MN MO MP MQ MR MS MT MU MV MW MX MY MZ N NA NB NC ND NE NF NG NH NI NJ NK NL NM NN NO NP NQ NR NS NT NU NV NW NX NY NZ O OA OB OC OD OE OF OG OH OI OJ OK OL OM ON OO OP OQ OR OS OT OU OV OW OX OY OZ P PA PB PC PD PE PF PG PH PI PJ PK PL PM PN PO PP PQ PR PS PT PU PV PW PX PY PZ Q QA QB QC QD QE QF QG QH QI QJ QK QL QM QN QO QP QQ QR QS QT QU QV QW QX QY QZ R RA RB RC RD RE RF RG RH RI RJ RK RL RM RN RO RP RQ RR RS RT RU RV RW RX RY RZ S SA SB SC SD SE SF SG SH SI SJ SK SL SM SN SO SP SQ SR SS ST SU SV SW SX SY SZ T TA TB TC TD TE TF TG TH TI TJ TK TL TM TN TO TP TQ TR TS TT TU TV TW TX TY TZ U UA UB UC UD UE UF UG UH UI UJ UK UL UM UN UO UP UQ UR US UT UU UV UW UX UY UZ V VA VB VC VD VE VF VG VH VI VJ VK VL VM VN VO VP VQ VR VS VT VU VV VW VX VY VZ W WA WB WC WD WE WF WG WH WI WJ WK WL WM WN WO WP WQ WR WS WT WU WV WW WX WY WZ X XA XB XC XD XE XF XG XH XI XJ XK XL XM XN XO XP XQ XR XS XT XU XV XW XX XY XZ Y YA YB YC YD YE YF YG YH YI YJ YK YL YM YN YO YP YQ YR YS YT YU YV YW YX YY YZ Z ZA ZB ZC ZD ZE ZF ZG ZH ZI ZJ ZK ZL ZM ZN ZO ZP ZQ ZR ZS ZT ZU ZV ZW ZX ZY ZZ Total Number of letters 676>>
  1 个评论
Walter Roberson
Walter Roberson 2018-9-2
It is not clear what your question or solution is?
The line indicates 676 solutions but you have printed out 702 solutions. Because each letter appears on its own as well as in pairs, you get 676+26 solutions.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by