How to import date time format from excel

2016 12 2
3 个回答
更新时间：2016 12 4
9 次查看（30 天）

0 个投票

i have data in excel like
4:46:32 1.257375
5:16:32 1.286917
4:48:13 2.274518
5:03:13 2.274042
4:33:38 1.595688
4:48:37 1.591687
when i import this data into Matlab using xlsread, it looks like
0.198981481481482 1.257375
0.219814814814815 1.286917
0.200150462962963 2.274518
0.210567129629630 2.274042
0.190023148148148 1.595688
0.200428240740741 1.591687
but i want it in original format.

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Jan
Jan 2016-12-2
I've formatted your text to make it readable.
AKHILESH KUMAR
AKHILESH KUMAR 2016-12-4
it's not working well. defines error in d=days(M(:,1)); d.Format='hh:mm:ss';

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回答（3 个）

Star Strider
Star Strider 2016-12-2

0 个投票

One approach is to re-convert them:
M = [0.198981481481482 1.257375
0.219814814814815 1.286917
0.200150462962963 2.274518
0.210567129629630 2.274042
0.190023148148148 1.595688
0.200428240740741 1.591687];
hmsv = datestr(datenum(M(:,1)), 'hh:mm:ss');
Mc = {hmsv, M(:,2)}; % Output Cell Array
Jan
Jan 2016-12-2
编辑：Jan 2016-12-2

0 个投票

dv = datevec(0.198981481481482);
ds = sprintf('%d:%d:%d', dv(4:6))
This would insert a leading zero:
datestr(0.198981481481482, 13)
>> '04:46:32'
Peter Perkins
Peter Perkins 2016-12-2

0 个投票

Or with durations and a table:
>> M = [0.198981481481482 1.257375
0.219814814814815 1.286917
0.200150462962963 2.274518
0.210567129629630 2.274042
0.190023148148148 1.595688
0.200428240740741 1.591687];
>> d = days(M(:,1)); d.Format = 'hh:mm:ss';
>> x = M(:,2);
>> t = table(d,x)
t =
d x
________ ______
04:46:32 1.2574
05:16:32 1.2869
04:48:13 2.2745
05:03:13 2.274
04:33:37 1.5957
04:48:37 1.5917

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