using sprintf for floating point numbers
3 次查看(过去 30 天)
显示 更早的评论
optEnergyCost=[42 36 28.5 26 39.7 25 57047]
optEnergyCostString=sprintf('%g',optEnergyCost)
optEnergyCostString=strrep(optEnergyCostString,'42','Route_1');
optEnergyCostString=strrep(optEnergyCostString,'36','Route_1');
optEnergyCostString=strrep(optEnergyCostString,'28.5','Route_2');
optEnergyCostString=strrep(optEnergyCostString,'26','Route_2');
optEnergyCostString=strrep(optEnergyCostString,'39.7','Route_1');
optEnergyCostString=strrep(optEnergyCostString,'25','Route_1');
but results are
optEnergyCostString =
423628.52639.72557046.5 how to get this as optEnergyString= route1 route1 route2 route2 route1 route1 57047
3 个评论
Image Analyst
2016-12-16
And I answered it there: http://www.mathworks.com/matlabcentral/answers/317037-replace-numbers-with-letters-in-a-vector-or-matrix#answer_247544 so your code will look normal.
By the way, for next time, read this http://www.mathworks.com/matlabcentral/answers/13205#answer_18099
采纳的回答
James Tursa
2016-12-16
编辑:James Tursa
2016-12-16
You don't have a semi-colon after this line:
optEnergyCostString=sprintf('%g',optEnergyCost)
so this result gets displayed to the screen. Then the other lines do the strrep stuff, but you don't ever display those results. So the only thing that gets displayed to the screen is the result of that first line, fooling you into thinking that that is the final result of the code (which it isn't), even though all of the other string replacements actually took place. All you need to do is simply examine optEnergyCostString after the code gets run.
To get your desired result, you will need to add a trailing space to your replacement strings.
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Environment and Settings 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!