using sprintf for floating point numbers
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optEnergyCost=[42 36 28.5 26 39.7 25 57047]
optEnergyCostString=sprintf('%g',optEnergyCost)
optEnergyCostString=strrep(optEnergyCostString,'42','Route_1');
optEnergyCostString=strrep(optEnergyCostString,'36','Route_1');
optEnergyCostString=strrep(optEnergyCostString,'28.5','Route_2');
optEnergyCostString=strrep(optEnergyCostString,'26','Route_2');
optEnergyCostString=strrep(optEnergyCostString,'39.7','Route_1');
optEnergyCostString=strrep(optEnergyCostString,'25','Route_1');
but results are
optEnergyCostString =
423628.52639.72557046.5 how to get this as optEnergyString= route1 route1 route2 route2 route1 route1 57047
3 个评论
Jan
2016-12-16
You are funny. How could we know what you find "correct". All we see is the code which does what the code does. But what do you want instead?
summyia qamar
2016-12-16
Image Analyst
2016-12-16
And I answered it there: http://www.mathworks.com/matlabcentral/answers/317037-replace-numbers-with-letters-in-a-vector-or-matrix#answer_247544 so your code will look normal.
By the way, for next time, read this http://www.mathworks.com/matlabcentral/answers/13205#answer_18099
采纳的回答
James Tursa
2016-12-16
编辑：James Tursa
2016-12-16
You don't have a semi-colon after this line:
optEnergyCostString=sprintf('%g',optEnergyCost)
so this result gets displayed to the screen. Then the other lines do the strrep stuff, but you don't ever display those results. So the only thing that gets displayed to the screen is the result of that first line, fooling you into thinking that that is the final result of the code (which it isn't), even though all of the other string replacements actually took place. All you need to do is simply examine optEnergyCostString after the code gets run.
To get your desired result, you will need to add a trailing space to your replacement strings.
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