check with all parameter except its own

2016 12 17
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更新时间：2016 12 18
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3 5 1
5 2 2
2 5 2
5 3 1
5 1 3
7 0 2
6 1 2
6 0 3
1 1 7
1 4 4
2 1 6
5 4 0
take 3+5=8--which is not equal to 9
so loop again rotate
take 3+2=5--not equal to 9
same in this manner 5+1=6 not valid 5+5=10 no same as this start from next entry and do process,take allentry as row wise if answer valid than loop stop and do for next element process

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David Barry
David Barry 2016-12-17
I've read that a couple of times now and still have no idea what you are asking. Can you explain it better?
Pratik Anandpara
Pratik Anandpara 2016-12-17
take element of matrix and sum with next element and check total =10 if not than take next element and again check sum
matrix(1,1)=3
3+5=8
3+1=4
3+5=8
3+2=8
3+2=5
3+2=5
3+2=5
3+2=5......3+7=10 loop stop
print-3 is valid
now matrix(1,2)=5
5+1=6
5+5=10...loop stop
5 is valid
matrix(1,3)=1
1+5=6
1+2=3
1+2=3
1+2=3...check with all other elements..except its own
David Barry
David Barry 2016-12-17
No still don't get it. Please upload a mat file containing your matrices.
Pratik Anandpara
Pratik Anandpara 2016-12-17
编辑：Pratik Anandpara 2016-12-17
mat file is more complicated i take example matrix :
1 2 3
4 5 6
7 8 9
goal is total=10
now take 1+2=3
1+3=4...1
1+4=5
1+5=6
1+6=7
1+7=8
1+8=9
1+9=10
stop this process now
print...1 is valid after 8 process
now take 2+3=5
2+4=6
2+5=7
2+6=8
2+7=9
2+8=10
print...2 is valid 6 process
3+4=7
3+5=8
3+6=9
3+7=10....3 is valid after 4 process
4+5=9
4+6=10....4 is valid after 2 process
now
5+6=11
5+7=12.......upto 5+4=9
5 is not valid(not take own sum)
6+7=13.6+8=14...6+9=15...6+1=7...6+2=8...6+3=9...6+4=10
6 is valid after 7 process
like this take row wise sequence...random matrix take but process same
Pratik Anandpara
Pratik Anandpara 2016-12-17
@david barry...still?....i will mail you if you stil not get
Image Analyst
Image Analyst 2016-12-17
He might have given up because it's not well explained. So do you want to add every element to every other element, or even all possible other elements, until you find all the combinations that equal some desired integer value?
I have two more questions. (2) How large could this matrix be? and (3) have you tried a intuitive and simple brute force "for" loop?
Pratik Anandpara
Pratik Anandpara 2016-12-17
use any loop ..matrix is mostly n*3 ..i tried force also but not set there
Image Analyst
Image Analyst 2016-12-17
Let's see your brute force for loop attempt.
David Barry
David Barry 2016-12-17
Yes I have given up. Poor explanation, no code and no data. I'm out.
Jan
Jan 2016-12-17
I do not understand the explanations also. What do you want to achieve?

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KSSV
KSSV 2016-12-18

0 个投票

Let A be your matrix.
B=A(:);
N = length(B);
iwant=zeros(N,2);
for i=1:N
count=0;
C=setdiff(B,B(i));
for j = 1:N-1
count=count+1;
if B(i)+C(j)==10
iwant(i,:)=[B(i) count];
break
end
end
end

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KSSV
KSSV 2016-12-18
count is not required ...You can directly take j in place of count.

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