How to access elements in a convoluted cell array.

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jungdnb
jungdnb 2016-12-23
评论： Image Analyst 2016-12-27
Hello and happy holidays to everyone.
I have an convoluted cell array IZ, with the size 1x12, that looks like this
IZ =
Columns 1 through 7
'4 8 12 16' '15 26 30 34' '4 8 12 16' '4 8 12 16' '4 15 17 21' '3 7 9 28' '3 7 9 28'
Columns 8 through 12
'3 7 9 28' '3 7 9 28' '3 14 16 35' '3 14 16 35' '3 9 11 30'
I know, I can access the single columns by typing IZ{x}, where x is the column index. But how can I access for example say third element of first column? Many thanks and greetings.

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采纳的回答

Jan
Jan 2016-12-26
What is "the 3rd element of the 1st column"? Do you mean the 12 as a number?
IZ = {'4 8 12 16', '15 26 30 34', '4 8 12 16'} % The rest does not matter here
FirstCol = IZ{1};
Number = sscanf(FirstCol, '%f');
Value = Number(3)
Or is the "3rd element" the 3rd character of the string? Please clarify this.
  1 个评论
jungdnb
jungdnb 2016-12-27
编辑：jungdnb 2016-12-27
I mean the number 12 as a number. I don't understand the line FirstCol = IZ{1}, is 1 the index of first column? I try your suggestion like this:
for idx=1:length(IZ)
Col = IZ{idx};
Number = sscanf(Col, '%f');
Value = Number(3)
end
Thank you, it works perfect.

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更多回答（1 个）

Image Analyst
Image Analyst 2016-12-26
I don't know what convoluted means. To me it means very complicated but some people use it to mean "convolved" like the result of a convolution operation. Anyway.....
Try this:
IZ = {'4 8 12 16',...
'15 26 30 34',...
'4 8 12 16',...
'4 8 12 16',...
'4 15 17 21',...
'3 7 9 28',...
'3 7 9 28',...
'3 7 9 28',...
'3 7 9 28',...
'3 14 16 35',...
'3 14 16 35',...
'3 9 11 30'}
% IZ is a row vector of cells with 12 columns - "1×12 cell array"
% First get the first cell contents.
% First column is a string with 4 numbers and spaces in it.
col1String = IZ{1} % Extract contents into a string '4 8 12 16'
% Get third element of the first column.
% The third element of that string is a space.
element3 = col1String(3) % This will be a space.
  2 个评论
jungdnb
jungdnb 2016-12-27
Thx, this is also useful for me, but for antoher problem. I meant with "third element" the number 12, or with ongoing number of columns, numbers 30, 17, 9, 16, etc.

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