Helping with the plot of a function

2012 3 13
1 个回答
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0 个投票

Hello!! I am trying to plot a function in freq-domain that decrease with f, I should get a kind of sin that decrease when time goes by, but I am not getting it. This is the code Tc=1*10^-3;
f=linspace(0,10000000);
R=zeros(size(f));
for a=1:1:100
R(f)=i*Tc*sinc(a(f)*Tc/2)*sin(pi*a(f)*Tc/2);
end
plot(f,R(f))
Please, someone could help.
Thanks in advance, Nicolas

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回答（1 个）

Jan
Jan 2012-3-13

0 个投票

  • Is the multiplication by i intented?
  • What is Tc?
  • a is the scalar loop counter, therefore a(f) should fail.
  • You assign R(f) in the loop, but this does not depend on the loop counter a.

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Nicolas
Nicolas 2012-3-13
Hello Jam!
i is the imaginatary unit and I want to multiply by it, then Tc is just a period that I defined before. I saw what you mean and now I modified my code but, now I can get the plot buut nothing is on it
Tc=1*10^-3;
f=linspace(0.1,2e6);
for aux=1:1:100;
R(aux)=i*Tc*sinc(f(aux).*Tc/2)*sin(pi*f(aux).*Tc/2);
end
plot(f,R(aux))
thanks, I dont know where is the problem
Nicolas
Nicolas 2012-3-13
In fact, when I check in the workspace it appear that aux is a single value = 100, not a vector....
Jan
Jan 2012-3-13
Yes, aux is a scalar. This is the expected and wanted behaviour of a FOR-loop. Try this:
for i = 1:10; disp(i); x(i) = i*i; end, disp(x)
For your problem: "plot(f, R)" will use all elements of R.

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Nicolas
Nicolas
2012-3-13

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