清空筛选条件
清空筛选条件

Helping with the plot of a function

2 次查看（过去 30 天）
Nicolas
Nicolas 2012-3-13
Hello!! I am trying to plot a function in freq-domain that decrease with f, I should get a kind of sin that decrease when time goes by, but I am not getting it. This is the code Tc=1*10^-3;
f=linspace(0,10000000);
R=zeros(size(f));
for a=1:1:100
R(f)=i*Tc*sinc(a(f)*Tc/2)*sin(pi*a(f)*Tc/2);
end
plot(f,R(f))
Please, someone could help.
Thanks in advance, Nicolas

请先登录，再回答此问题。

回答（1 个）

Jan
Jan 2012-3-13
  • Is the multiplication by i intented?
  • What is Tc?
  • a is the scalar loop counter, therefore a(f) should fail.
  • You assign R(f) in the loop, but this does not depend on the loop counter a.
  3 个评论
显示 1更早的评论
Nicolas
Nicolas 2012-3-13
In fact, when I check in the workspace it appear that aux is a single value = 100, not a vector....
Jan
Jan 2012-3-13
Yes, aux is a scalar. This is the expected and wanted behaviour of a FOR-loop. Try this:
for i = 1:10; disp(i); x(i) = i*i; end, disp(x)
For your problem: "plot(f, R)" will use all elements of R.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Numerical Integration and Differential Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by