Determining the second last row
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Hi there,
How would you code the number of rows minus one? Below I use size() to find the number of rows, but I want to set nrows to the number or rows minus 1.
Many thanks
sch_cycle=xlsread('C:\Autonomie practice\cycle.xls','Input_data');
nrows = size(sch_cycle,1);
采纳的回答
Jonathan Sullivan
2012-3-16
sch_cycle=xlsread('C:\Autonomie practice\cycle.xls','Input_data');
nrows = size(sch_cycle,1)-1;
更多回答（1 个）
Dr. Seis
2012-3-16
If you mean you want to set "sch_cycle" to have nrows - 1, then no need to actually determine "nrows" beforehand (just use "end"):
sch_cycle = sch_cycle(1:end-1,:);
You can setup an "if" statement in order to make sure "nrows" is greater than 1.
3 个评论
Sean de Wolski
2012-3-16
or you could use max:
sch_cycle(max(1,size(sch_cycle,1)-1),:)
Dr. Seis
2012-3-16
Looks like "end" will still work there, too:
sch_cycle(1:max(1,end-1),:); % For all rows except last row
sch_cycle(max(1,end-1),:); % For just second to last row
John
2012-3-16
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