Replace multiple intervals in array with NaN - No loops
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Hi
I am working on a project with a lot of data. In the area of 10.000.000 rows. I therefore cannot use for loops. The data has to be cleaned, with respect to certain parameters. These parameters are found independently and are not on measured with the same timesteps. Below is a simplified example that explains the idea of the problem. :)
The main dataset, let's call it:
dataset = 1:30;
Two arrays are now given. They indicate intervals within which measurements has to replaced with NaN.
upperbound = [2,5,10,18,27];
lowerbound = [0,3,8,15,25];
With a for loop I would normally say:
for i = 1:length(upperbound);
dataset(lowerbound(i):upperbound(i)) = NaN;
end
But with so much data this is not possible.
Do any of you have a good idea to solve this ?
2 个评论
Jan
2017-2-14
The smallest lowerbound index is zero. Is this a typo, because indices must be >= 1?
Michael Madelaire
2017-2-15
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