find for sign changes

203 次查看（过去 30 天）
Kugen Raj
Kugen Raj 2012-3-17
评论： Walter Roberson 2021-3-4
Columns 49 through 56
0.8710 0.9483 1.0408 1.1538 1.2956 1.4796 1.7292 2.0885
Columns 57 through 64
2.6538 3.6815 6.1847 119.1838 -118.8424 -5.8436 -3.3407 -2.3137
Above is part of my results. I need to find for value that changes from positive to negative. In the above data, after 119.1838(column 60) the -118.8424(column 61) appears. I need to find this value. Hoe can I do this?

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2012-3-17
find(x(1:end-1)>0 & x(2:end) < 0)
Another approach that might be close enough for your purposes:
find(diff(x>=0),1)
  4 个评论
显示 2更早的评论
Jan
Jan 2012-3-18
But what happens with your first approach for [1, 0, -1]?
The OP must decide this detail.
Walter Roberson
Walter Roberson 2012-3-18
In the case of [1, 0, -1] there is no position at which the value is positive and the next value is negative :)

请先登录，再进行评论。

更多回答（3 个）

Jan
Jan 2012-3-17
Walter's method detects multiple sign changes also. This finds the first negative number only, but this meets your problem description also:
index = find(x < 0, 1, 'first')
Rasmus Herlo
Rasmus Herlo 2020-1-22
编辑：Rasmus Herlo 2020-1-22
Finding any place where the sign changes, either from neg to pos or from pos to neg could also be done in general by this:
Idx_Change = sort([strfind(x>=0, [0 1]) strfind(x>=0, [1 0])]);
Alireza Ahani
Alireza Ahani 2021-3-4
@Walter Roberson is right,
but when I checked with a dataset that includes zero-down-crosing event, they would be ignored, so I added some lines to his:
ZDCI = find(x(1:end-1)>0 & x(2:end) < 0); % zero down crossing index
Zero_indx = find(x == 0);
k = find( x(Zero_indx-1) > 0);
ZDCI = sort([ZDCI Zero_indx(k)]);
  1 个评论
Walter Roberson
Walter Roberson 2021-3-4
If the task is zero down crossing and zeros can be encountered, then the above code is not correct, as it does not take into account multiple zeros. For example for zero down crossing, you might have +1 followed by 5 zeros, followed by -1. The zeros could, for example, be present due to filtering of values that were close to zero, such as due to measurement noise on a sigmoid that crossed zero. Detection for such cases cannot be restricted to any fixed finite number of look-back.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by