Averaging of "similar data" in vector

Question

Jason 2017-2-21

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/326168-averaging-of-similar-data-in-vector

编辑： Jan 2017-2-21

采纳的回答： Jan

在 MATLAB Online 中打开

Hi. I have a vector x as below. There are clearly "groups" of data. I want to find the average of each group

This was my attempt, but I've come to a halt: Not sure what to do next.

D=unique(double(x))
F=diff(D)
F1=F;
F1(F1<20)=[]
idx=find(F1==F)
x =
    72×1 uint16 column vector
      13
      13
      13
      13
      14
      14
      14
      14
      14
      58
      58
      58
      59
      59
      59
      59
      59
      60
     103
     103
     104
     104
     104
     104
     104
     104
     104
     193
     193
     194
     194
     194
     194
     194
     195
     195
     238
     238
     238
     239
     239
     239
     239
     239
     239
     283
     283
     284
     284
     284
     284
     284
     284
     284
     328
     329
     329
     329
     329
     329
     329
     329
     330
     373
     374
     374
     374
     374
     374
     375
     375
     375

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Answer 1

Jan 2017-2-21

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/326168-averaging-of-similar-data-in-vector#answer_255731

编辑：Jan 2017-2-21

在 MATLAB Online 中打开

If the blocks are identified by having a maximum distance thresh from the lowest to the highest element:

% UNTESTED
n      = length(x);
thresh = 20
group  = zeros(size(x));
lim    = x(1) + thresh;
index  = 1;
for k = 1:n
  if x(k) > lim
    index = index + 1;
    lim   = x(k) + thresh;
  end
  group(k) = index;
end
Y = splitapply(@mean, x, group);  % Needs Matlab >= 2015b

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Answer 2

Jason 2017-2-21

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/326168-averaging-of-similar-data-in-vector#answer_255722

在 MATLAB Online 中打开

array = x';
sortedArray = sort(array);
nPerGroup = diff(find([1 (diff(sortedArray) > threshold) 1]));
groupArray = mat2cell(sortedArray,1,nPerGroup)
l=numel(groupArray)
m=zeros(l,1)
for i=1:l
   Gm=groupArray{:,i}
   m(i,1)=round(mean(Gm(:)))
end