How to pass values to a vector inside an anonymous function for ezplot?

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Ezz El-din Abdullah 2017-3-5

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https://ww2.mathworks.cn/matlabcentral/answers/328221-how-to-pass-values-to-a-vector-inside-an-anonymous-function-for-ezplot

评论： Guillaume 2017-3-6

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I wonder how can I benefit from passing additional parameter for ezplot function.

I'm trying to plot implicit function that has a vector th inside which has the problem.

Here is the code:

delta = pi*[1 2 3];
m = 1:100;
th{1,1}(1:100) = 2*pi*m*delta(1); 
th{2,1}(1:100) = 2*pi*m*delta(2); 
th{3,1}(1:100) = 2*pi*m*delta(3); 
myfun = @(x,y,k) x + y.*th{k,1}(1:100) + k;   
for k = 1:3
  ezplot(@(x,y)myfun(x,y,k));
  hold on
end

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Ezz El-din Abdullah 2017-3-6

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What I mean by three lines is that the equation x + y*th + k is satisfied.

Let's consider the simplest case when th is a scalar. Since th has the vector delta which has three values in it. It will produce three lines. I know that the output of ezplot is just 1x1 so when th is a scalar the ezplot will not complain.

The problem comes when we consider the th as a vector like I wrote in the code.

So for each value of delta which corresponds to the first vector of the th 2D matrix (as you explained) I would like to "sort of" convert this vector into a just symbolic 1x1 that ezplot output can produce. So actually, I don't know what myfun(x,y,k) should produce.

It happens that for a scalar value of th it produced this figure:

For that case:

>> myfun(1,1,1)
ans =
     2

I hope I'm clear now and thanks.

Guillaume 2017-3-6

在 MATLAB Online 中打开

I understand everything you wrote except the I would like to "sort of" convert this vector into a just symbolic 1x1 that ezplot output can produce. It doesn't sound that you actually know what you want.

ezplot plots where myfun(x, y) == 0. What does equal to 0 mean when myfun(x, y) is a vector of 100 values? Do you want the zeros of the function

f(x, y) = x + a*y + k

for 100 different scalar a and 3 different scalar k, resulting in 300 plots?

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