Can i get a DES algorithm source code in matlab?

17 次查看(过去 30 天)
I am trying to encrypt a message using DES encryption... I need a source code to run the program.. If anyone has it, please share the link. I tried out the following link..https://www.mathworks.com/matlabcentral/fileexchange/37847-data-encryption-standard--des- but, when i tried to run the program, it showed Error as " not enough input arguments" in the line 64 Initialization part..
  2 个评论
Jan
Jan 2017-3-16
编辑:Jan 2017-3-16
@John D'Errico: Why did you close this question? I know, a simple search in the internet would reveal a link directly. But this concerns many questions.
DES encryption is not strong, such that the question does not collide with the export restrictions of the USA. Therefore this tool can be found in the FileExchange in opposite to AES.
Aishwarya Rajan
Aishwarya Rajan 2017-3-16
编辑:Aishwarya Rajan 2017-3-16
Thank you sir.. I have already been using a DES source code, but the problem was i have to encrypt a message using a 16 bit secret key, but each and every time, it encrypts the key, instead of encrypting the message, I can't fathom why.. i applied the code [encryptt,en]=des(message,key).
my souce code of DES is as follows:
function [t C]=des( M,Key)
tic;
M = 'AF88888888555456';
%K = '1256984563214569';
K=Key;
MB=[];
for i=1:16
Mi=M(i);
MBi=['0000',dec2bin(hex2dec(Mi))];
MBi=MBi(end-3:end);
MBi=[str2num(MBi(1)),str2num(MBi(2)),str2num(MBi(3)),str2num(MBi(4))];
MB=[MB,MBi];
end
M=MB ;
KB=[];
for i=1:16
Ki=K(i);
KBi=['0000',dec2bin(hex2dec(Ki))];
KBi=KBi(end-3:end);
KBi=[str2num(KBi(1)),str2num(KBi(2)),str2num(KBi(3)),str2num(KBi(4))];
KB=[KB,KBi];
end
K=KB;
E=[32, 1, 2, 3, 4, 5; 4, 5, 6, 7, 8, 9; 8, 9,10,11,12,13; 12,13,14,15,16,17; 16,17,18,19,20,21; 20,21,22,23,24,25; 24,25,26,27,28,29; 28,29,30,31,32,1];
S1=[14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7; 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8; 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0; 15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13];
S2=[15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10; 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5; 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15; 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9];
S3=[10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8; 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1; 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7; 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12];
S4=[7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15; 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9; 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4; 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14];
S5=[2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9; 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6; 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14; 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3];
S6=[12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11; 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8; 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6; 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13];
S7=[4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1; 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6; 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2; 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12];
S8=[13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7; 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2; 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8; 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11];
P=[16,7,20,21,29,12,28,17,1,15,23,26,5,18,31,10,2,8,24,14,32,27,3,9,19,13,30,6,22,11,4,25];
PC1=[57,49,41,33,25,17,9,1,58,50,42,34,26,18,10,2,59,51,43,35,27,19,11,3,60,52,44,36,63,55,47,39,31,23,15,7,62,54,46,38,30,22,14,6,61,53,45,37,29,21,13,5,28,20,12,4];
PC2=[14,17,11,24,1,5,3,28,15,6,21,10,23,19,12,4,26,8,16,7,27,20,13,2,41,52,31,37,47,55,30,40,51,45,33,48,44,49,39,56,34,53,46,42,50,36,29,32];
Ki=zeros(16,48);
K_PC1=K(PC1);
C0=K_PC1(1:28);
D0=K_PC1(29:56);
for i=1:16
if i==1||i==2||i==9||i==16
C0=[C0(2:end),C0(1)];
D0=[D0(2:end),D0(1)];
else
C0=[C0(3:end),C0(1:2)];
D0=[D0(3:end),D0(1:2)];
end
K_LS=[C0,D0];
Ki(i,:)=K_LS(PC2);
end
L=M(1:32);
R=M(33:64);
for i=1:16
E0=reshape(E',1,48);
R_E=R(E0);
R_Ki=mod(R_E+Ki(i,:),2);
B=R_Ki(1:6);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S1(x,y))];
C=C(end-3:end);
C1=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(7:12);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S2(x,y))];
C=C(end-3:end);
C2=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(13:18);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S3(x,y))];
C=C(end-3:end);
C3=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(19:24);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S4(x,y))];
C=C(end-3:end);
C4=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
tc=0.21145+0.21145;
B=R_Ki(25:30);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S5(x,y))];
C=C(end-3:end);
C5=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(31:36);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S6(x,y))];
C=C(end-3:end);
C6=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(37:42);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S7(x,y))];
C=C(end-3:end);
C7=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(43:48);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S8(x,y))];
C=C(end-3:end);
C8=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
C=[C1,C2,C3,C4,C5,C6,C7,C8];
R_P=C(P);
TEMP=L;
L=R;
R=mod(TEMP+R_P,2);
end
TEMP=L;
L=R;
R=TEMP;
C=[L,R];
CS=[];
C=num2str(C); pos=find(C~=' ');
C=C(pos);
for i=1:4:61
Ci=C(i:i+3);
CS=[CS,num2str(dec2hex(bin2dec(Ci)))];
end
C=CS;
t=tc;
end

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Numeric Types 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by