Info

此问题已关闭。 请重新打开它进行编辑或回答。

How do I use a for loop?

1 次查看(过去 30 天)
James Pain
James Pain 2017-3-17
关闭: MATLAB Answer Bot 2021-8-20
Hello, I'm currently trying to make an approximation method in matlab, and this is what I have currently:
function T = Dog(A,S)
L=randi([-9,9],3,1);
H=L/norm(L);
O=(inv((A-(A(3,3)*eye(3)))))*(H);
Y=O/norm(O);
G=(inv((A-(A(3,3)*eye(3)))))*(Y);
D=G/norm(G);
F=(inv((A-(A(3,3)*eye(3)))))*(D);
R=F/norm(F);
W=(inv((A-(A(3,3)*eye(3)))))*(R);
X=W/norm(W);
V=(inv((A-(A(3,3)*eye(3)))))*(X);
K=V/norm(V);
N=(K.*K)./(K.*V);
T=N+S;
end
Now I was wondering is there someway of using a for loop from lines 3 to 13, so that instead of having to change the name of the variable each time it would simply replace it with with the one that came before it?
  1 个评论
James Pain
James Pain 2017-3-17
I had the Approximation method wrong originally, but I've now edited the question properly.

回答(1 个)

Thorsten
Thorsten 2017-3-17
编辑:Thorsten 2017-3-17
F=randn(3,1)./W;
for i = 1:5
Q = inv(A - S*eye(3))*F;
F = W./Q;
W = Q;
end
J = (F.*F)./(Q.*F);
T = J + S;
  3 个评论
Jan
Jan 2017-3-17
编辑:Jan 2017-3-17
@James: The reply remains almost the same. Can you apply the required changes by your own?
You can create C = A - S*eye(3) once before the loop. Then for numerical stability replace the explicit inversion by:
Q = C \ F;
James Pain
James Pain 2017-3-17
Your Right, I've figured out how to do it, cheers

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by