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How do I use a for loop?

1 次查看(过去 30 天)
James Pain
James Pain 2017-3-17
关闭: MATLAB Answer Bot 2021-8-20
Hello, I'm currently trying to make an approximation method in matlab, and this is what I have currently:
function T = Dog(A,S)
L=randi([-9,9],3,1);
H=L/norm(L);
O=(inv((A-(A(3,3)*eye(3)))))*(H);
Y=O/norm(O);
G=(inv((A-(A(3,3)*eye(3)))))*(Y);
D=G/norm(G);
F=(inv((A-(A(3,3)*eye(3)))))*(D);
R=F/norm(F);
W=(inv((A-(A(3,3)*eye(3)))))*(R);
X=W/norm(W);
V=(inv((A-(A(3,3)*eye(3)))))*(X);
K=V/norm(V);
N=(K.*K)./(K.*V);
T=N+S;
end
Now I was wondering is there someway of using a for loop from lines 3 to 13, so that instead of having to change the name of the variable each time it would simply replace it with with the one that came before it?
  1 个评论
James Pain
James Pain 2017-3-17
I had the Approximation method wrong originally, but I've now edited the question properly.

回答(1 个)

Thorsten
Thorsten 2017-3-17
编辑:Thorsten 2017-3-17
F=randn(3,1)./W;
for i = 1:5
Q = inv(A - S*eye(3))*F;
F = W./Q;
W = Q;
end
J = (F.*F)./(Q.*F);
T = J + S;
  3 个评论
Jan
Jan 2017-3-17
编辑:Jan 2017-3-17
@James: The reply remains almost the same. Can you apply the required changes by your own?
You can create C = A - S*eye(3) once before the loop. Then for numerical stability replace the explicit inversion by:
Q = C \ F;
James Pain
James Pain 2017-3-17
Your Right, I've figured out how to do it, cheers

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