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please provide with the color identification base paper for the following code
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a=0;
b=0;
c=0;
p=0;
p1=0;
I=imread('E:\projectimages\imgs\clg.jpg')
imshow(I)
fnam=imread('E:\projectimages\imgs\clg.jpg');
figure,imshow(fnam)
for mm = 1:size(fnam,1)
for nn = 1:size(fnam,2)
if (fnam(mm,nn,2)) > fnam(mm,nn,1) && (fnam(mm,nn,2)) > fnam(mm,nn,3)
fnam(mm,nn,1) = fnam(mm,nn,1);
fnam(mm,nn,2) = fnam(mm,nn,2);
fnam(mm,nn,3) = fnam(mm,nn,3);
a=a+1;
%
else
fnam(mm,nn,1) = 0;
fnam(mm,nn,2) = 0;
fnam(mm,nn,3) = 0;
b=b+1;
end
end
end
p = a / (a + b);
p1 = p * 100;
imshow(fnam);
a = sprintf('Vegetation Pixel Count= %3d',a);
b = sprintf('Non Vegetation Pixel count= %3d',b);
c = sprintf('Percentage of area of veg is %3f %',p1);
msgbox(a);
msgbox(b);
msgbox(c);
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回答(1 个)
Walter Roberson
2017-3-23
There is no "paper" for that. The code just extracts the pixels for which the green component is greater than the red or blue, and calls those pixels "vegetation". That is not a robust way to calculate vegetation. For one thing, it leaves out all brown, but a lot of wood is brown.
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