for loop or str2num incorrectly adding 48 to results?

Question

Kirston Barton 2017-3-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/331632-for-loop-or-str2num-incorrectly-adding-48-to-results

评论： Kirston Barton 2017-3-24

I have the following code (which was part of a homework assignment, but I have solved the problem), I just don't understand why between lines 10 and 11, this code is adding 48 to the gg when it inserts it into vector q? I solved it by subtracting 48 from gg on line 10, but this makes no sense to me (first of all why I have to do it and second of all why is allows me to subtract 48 when I have converted it to a string on line 8). Can someone please explain what is going on here. It is driving me crazy! I have tried on two computers with tons of different inputs, completely closed and reopened matlab, cleared all values...It keeps happening.

a='1234567890'; aa='1234567890'; function b=add(a,aa) k=0; for i=10:-1:1 f=str2num(a(i))+str2num(aa(i))+k; if f > 10 g = num2str(f); gg=g(2); q(i)=gg; k=str2num(g(1)); else q(i)=f; end end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Michelangelo Ricciulli 2017-3-24

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/331632-for-loop-or-str2num-incorrectly-adding-48-to-results#answer_260110

在 MATLAB Online 中打开

It is doing that because every character of the string '10', is memorized in matlab with an encoding. So '0' is actually stored as a 48 and for example '1' is stored as 49, 'a' is 97 , etc...

If you want the number represented in a character, you should use

q(i)=str2num(gg);

because this will convert the char to an integer.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Kirston Barton 2017-3-24

This worked, thank you for pointing this out. Good thing to keep in mind for future functions!

请先登录，再进行评论。

Answer 2

Jan 2017-3-24

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/331632-for-loop-or-str2num-incorrectly-adding-48-to-results#answer_260111

编辑：Jan 2017-3-24

在 MATLAB Online 中打开

This is the effect of confusing the number 0 with the character '0'. When you add the character '0' to a number or append it to a numerical array, its ASCII value is used, and this is 48:

double('0')
x = 1
x = [x, '0']

The same happens for '1', which has the ASCII code 49.

You code contain several bugs:

The output b is not created
In the case f>10 you append a character to q(i), but in the other case you append the number f.
Defined before the loop if q is a double of char vector. Otherwise this depends on the first assignment.
What happens for f==10?

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Kirston Barton 2017-3-24

Hi Jan,

Thank you for looking at this so thoroughly. Like I said, it is a bit of homework, so I just cut this little loop out of the larger function so that I could see if the same problem repeated and so that I don't post my solution for other people. Don't worry, it all does fit into a larger story with all the variables populating and outputting somewhere. I really appreciate you taking a look and helping out with the primary question!

请先登录，再进行评论。