How to compare one column of one matrix with all columms of other matrix one by one? matlab 2014b

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Pooja Patel
Pooja Patel 2017-3-27
评论： Pooja Patel 2017-3-27
suppose N is 7x8 matrix, M is 7x8 matrix. both are different i want N(:,1)-M(:,1);N(:,1)-M(:,2);N(:,1)-M(:,3)...........N(:,2)-M(:,1);N(:,2)-M(:,2) and so on. how to do that? please help me. I am using matlab version 2014b.

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Guillaume
Guillaume 2017-3-27
编辑：Guillaume 2017-3-27
R2016b or later:
N - permute(M, [1 3 2])
Pre-R2016b:
bsxfun(@minus, N, permute(M, [1 3 2]))
will give you a 7x8x8 matrix where each (:, i, j) is N(:, i) - M(:, j)

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Jan
Jan 2017-3-27
编辑：Jan 2017-3-27
% With Matlab >= 2016b:
sM = size(M);
R = N - reshape(M, [sM(1), 1, sM(2)]);
% With Matlab < 2016b
R = bsxfun(@minus, N, reshape(M, [sM(1), 1, sM(2)]));
  1 个评论
Pooja Patel
Pooja Patel 2017-3-27
编辑：Pooja Patel 2017-3-27
I am using matlab 2014b. i have used sM = size(M);R = bsxfun(@minus, N, reshape(M, [sM(1), 1, sM(2)]));. but It is showing error in reshape "To RESHAPE the number of elements must not change."

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