How to compare one column of one matrix with all columms of other matrix one by one? matlab 2014b

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Pooja Patel 2017-3-27

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https://ww2.mathworks.cn/matlabcentral/answers/332137-how-to-compare-one-column-of-one-matrix-with-all-columms-of-other-matrix-one-by-one-matlab-2014b

评论： Pooja Patel 2017-3-27

suppose N is 7x8 matrix, M is 7x8 matrix. both are different i want N(:,1)-M(:,1);N(:,1)-M(:,2);N(:,1)-M(:,3)...........N(:,2)-M(:,1);N(:,2)-M(:,2) and so on. how to do that? please help me. I am using matlab version 2014b.

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Answer 1

Guillaume 2017-3-27

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https://ww2.mathworks.cn/matlabcentral/answers/332137-how-to-compare-one-column-of-one-matrix-with-all-columms-of-other-matrix-one-by-one-matlab-2014b#answer_260538

编辑：Guillaume 2017-3-27

在 MATLAB Online 中打开

R2016b or later:

N - permute(M, [1 3 2])

Pre-R2016b:

bsxfun(@minus, N, permute(M, [1 3 2]))

will give you a 7x8x8 matrix where each (:, i, j) is N(:, i) - M(:, j)

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Pooja Patel 2017-3-27

ohh yes, its working. thank you so much for your help.

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Answer 2

Jan 2017-3-27

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https://ww2.mathworks.cn/matlabcentral/answers/332137-how-to-compare-one-column-of-one-matrix-with-all-columms-of-other-matrix-one-by-one-matlab-2014b#answer_260537

编辑：Jan 2017-3-27

在 MATLAB Online 中打开

% With Matlab >= 2016b:
sM = size(M);
R = N - reshape(M, [sM(1), 1, sM(2)]);
% With Matlab < 2016b
R = bsxfun(@minus, N, reshape(M, [sM(1), 1, sM(2)]));

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Pooja Patel 2017-3-27

编辑：Pooja Patel 2017-3-27

I am using matlab 2014b. i have used sM = size(M);R = bsxfun(@minus, N, reshape(M, [sM(1), 1, sM(2)]));. but It is showing error in reshape "To RESHAPE the number of elements must not change."

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