C++ pointers and variables

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Carlos
Carlos 2017-4-3
评论: Guillaume 2017-4-4
Dear experts,
I am trying to convert the following C++ code to a matlab code:
double buffer = 72.0;
double *pBuffer = &buffer;
t = sizeof(buffer));
Does anyone know to solve this question?
Thank you in advance.
Carlos

采纳的回答

Jan
Jan 2017-4-3
buffer = 72;
You do neither need a pointer in Matlab nor does the the size of the type matter.
  4 个评论
Carlos
Carlos 2017-4-4
Thank you Jan. I made it.
Guillaume
Guillaume 2017-4-4
If you're using this filexchange sizeof you're using it incorrectly. The correct code should have been:
calllib(libstring,'SetSystemParameter',MAXIMUM_RANGE,pRecord31,sizeof('double'));
Or you could just not have bothered and pass 8 directly, since scalar double are always 8 bytes.
Note that matlab may have been clever enough to automatically make the conversion from double to void pointer, so possibly this may have been enough:
value = 72;
calllib(libstring,'SetSystemParameter',MAXIMUM_RANGE, value, 8)

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