清空筛选条件
清空筛选条件

How can I change the radius of a circle pointeur

3 次查看（过去 30 天）
Marie BILLARD
Marie BILLARD 2017-4-11
评论： Marie BILLARD 2017-4-12
Hi, I'm using the "myginput.m" function and I would like to change the radius of my circle pointer. However, I haven't succeeded. Would anybody have a or the solution ? Thank you in advance.
  2 个评论
KSSV
KSSV 2017-4-11
What is this function myginput.m? And where you want to change the pointer?
Marie BILLARD
Marie BILLARD 2017-4-11
I found myginput.m function on this link : https://fr.mathworks.com/matlabcentral/fileexchange/12770-myginput So I can change my "arrow" pointer on "circle" pointer. But I don't know how to increase the radius of this circle.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Jan
Jan 2017-4-11
编辑：Jan 2017-4-12
This function can set exactly the same pointers as explained in the documentation: See doc figure "pointers" . You cannot set the radius of the circle pointer.
If you want to choose the radius freely, you need to draw the circle by your own.
[EDITED] For creating a 32x32 pointer, see the "PointerShapeCData" point in the posted link.
CData = [ ...
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1; ...
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2; ...
0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 2, 2, 2, 2, 0, 0; ...
0, 0, 0, 0, 0, 0, 0, 1, 2, 2, 0, 0, 0, 0, 0, 0; ...
0, 0, 0, 0, 0, 1, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 0, 0, 0, 1, 2, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 0, 0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
LUT = [NaN, 1, 2]; % Transparent, black, white
Shape = LUT(CData + 1);
Shape = cat(2, Shape, fliplr(Shape));
Shape = cat(1, Shape, flipud(Shape));
figure('Pointer', 'custom', 'PointerShapeCData', Shape);
This is a circle with 32 pixels diameter with black pixels and a white circle inside. This is visible on light and dark images. If only the black circle is wanted, use: LUT = [NaN, 1, NaN]
Set the 'PointerShapeHotSpot' to [16, 16]. Note, that the center is not exactly at the midpoint of the circle. To get this create a circle with an odd number of pixels.

更多回答（1 个）

Thorsten
Thorsten 2017-4-11
You have to define your own pointer as a 16 x 16 matrix and then change the line in myginput that changes the pointer to use your pointer. See http://matlab.izmiran.ru/help/techdoc/creating_plots/figure12.html for details how to define a pointer.
  5 个评论
显示 3更早的评论
Guillaume
Guillaume 2017-4-12
编辑：Guillaume 2017-4-12
In which documentation can I find it ?
The one that comes with your copy of matlab! At least, R2017a says it can be 32x32.
At matlab command prompt:
web(fullfile(docroot, 'matlab/ref/figure-properties.html#property_d0e277605'))
Or you could just try and see if it works:
hfig = figure;
custompointer = ones(32); custompointer(2:end-1, 2:end-1) = nan; %32x32 square
hfig.Pointer = 'custom';
hfig.PointerShapeCData = custompointer;
edit: it would appear that 32x32 was added in R2016b

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Line Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by