How can I change the radius of a circle pointeur

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Marie BILLARD 2017-4-11

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https://ww2.mathworks.cn/matlabcentral/answers/334771-how-can-i-change-the-radius-of-a-circle-pointeur

评论： Marie BILLARD 2017-4-12

Hi, I'm using the "myginput.m" function and I would like to change the radius of my circle pointer. However, I haven't succeeded. Would anybody have a or the solution ? Thank you in advance.

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KSSV 2017-4-11

What is this function myginput.m? And where you want to change the pointer?

Marie BILLARD 2017-4-11

I found myginput.m function on this link : https://fr.mathworks.com/matlabcentral/fileexchange/12770-myginput So I can change my "arrow" pointer on "circle" pointer. But I don't know how to increase the radius of this circle.

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Answer 1

Jan 2017-4-11

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https://ww2.mathworks.cn/matlabcentral/answers/334771-how-can-i-change-the-radius-of-a-circle-pointeur#answer_262635

编辑：Jan 2017-4-12

在 MATLAB Online 中打开

This function can set exactly the same pointers as explained in the documentation: See doc figure "pointers" . You cannot set the radius of the circle pointer.

If you want to choose the radius freely, you need to draw the circle by your own.

[EDITED] For creating a 32x32 pointer, see the "PointerShapeCData" point in the posted link.

CData = [ ...
  0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1; ...
  0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2; ...
  0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 2, 2, 2, 2, 0, 0; ...
  0, 0, 0, 0, 0, 0, 0, 1, 2, 2, 0, 0, 0, 0, 0, 0; ...
  0, 0, 0, 0, 0, 1, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 0, 0, 0, 1, 2, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 0, 0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0; ...
  1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
LUT   = [NaN, 1, 2];   % Transparent, black, white
Shape = LUT(CData + 1);
Shape = cat(2, Shape, fliplr(Shape));
Shape = cat(1, Shape, flipud(Shape));
figure('Pointer', 'custom', 'PointerShapeCData', Shape);

This is a circle with 32 pixels diameter with black pixels and a white circle inside. This is visible on light and dark images. If only the black circle is wanted, use: LUT = [NaN, 1, NaN]

Set the 'PointerShapeHotSpot' to [16, 16]. Note, that the center is not exactly at the midpoint of the circle. To get this create a circle with an odd number of pixels.

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Marie BILLARD 2017-4-12

ok thank you @Jan Simon

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Answer 2

Thorsten 2017-4-11

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You have to define your own pointer as a 16 x 16 matrix and then change the line in myginput that changes the pointer to use your pointer. See http://matlab.izmiran.ru/help/techdoc/creating_plots/figure12.html for details how to define a pointer.

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Guillaume 2017-4-12

编辑：Guillaume 2017-4-12

在 MATLAB Online 中打开

In which documentation can I find it ?

The one that comes with your copy of matlab! At least, R2017a says it can be 32x32.

At matlab command prompt:

web(fullfile(docroot, 'matlab/ref/figure-properties.html#property_d0e277605'))

Or you could just try and see if it works:

hfig = figure;
custompointer = ones(32); custompointer(2:end-1, 2:end-1) = nan;  %32x32 square
hfig.Pointer = 'custom';
hfig.PointerShapeCData = custompointer;

edit: it would appear that 32x32 was added in R2016b

Marie BILLARD 2017-4-12