UTC time
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How to convert UTC time to time in YEAR MONTH DAY HH MM SS?
UTC is 1263403529
I need
13-Jan-2012 17:25:29
采纳的回答
C.J. Harris
2012-3-26
Grab the following file from the File Exchange:
Then call:
x = 1263403529;
y = datestr(utc2datenum(x));
6 个评论
Jisha
2012-3-26
C.J. Harris
2012-3-26
Ensure you have the 'utc2datenum.mexw32' file in the same location as 'utc2datenum.m'.
Jisha
2012-3-26
C.J. Harris
2012-3-26
Then that's your problem. MATLAB isn't recognising the '.mexw32' file since you are using a 64-bit version of MATLAB. You will have to recompile the source code in order to run it on your system.
Jisha
2012-3-26
Christoph Kessler
2024-2-29
What is the use if Answer requires a specific environment like 64 or 32-bit. Can you simply change without source code?
更多回答（3 个）
Steven Lord
2018-7-27
You can do this using datetime.
>> dt = datetime(1263403529, 'ConvertFrom', 'posixtime')
dt =
datetime
13-Jan-2010 17:25:29
James Tursa
2012-3-26
If this is "seconds since 1970-01-01 00:00:00 TAI" it is more properly called "unix time" or "posix time" or sometimes "epoch time", not UTC. E.g., see this article:
If that is the case you can simply calculate your result as:
x = 1263403529;
e = datenum('01-jan-1970 00:00:00');
y = datestr(e+x/86400,'dd-mm-yyyy hh:mm:ss');
4 个评论
C.J. Harris
2012-3-26
For the format '13-Jan-2012 17:25:29' the last line would have to be:
y = datestr(e+x/86400,'dd-mmm-yyyy HH:MM:SS');
James Tursa
2012-3-26
Oops. Thanks.
Geoff
2012-3-26
It's best to avoid string processing where it's not necessary:
e = datenum(1970,1,1,0,0,0);
James Tursa
2012-3-27
Well, I would assume e would be a one-time only calculation in which case the string is more readable IMO. But if the goal is to make this calculation faster then I would simply eliminate it altogether. E.g.,
y = datestr(719529+x/86400,'dd-mmm-yyyy HH:MM:SS');
along with a comment stating where the magic number 719529 comes from.
Uilke Stelwagen
2012-5-31
1 个投票
Wrote my own utc2datenum and discovered that 'UTC' 1263403529 is NOT "13-Jan-2012 17:25:29" but 1326475529 is. I.e. datestr(utc2datenum(1263403529)) = 13-Jan-2010 17:25:29, hence differing 2 years, while datestr(utc2datenum(1326475529)) = 13-Jan-2012 17:25:29. Best thing is to check a routine or algorithm with the 'UTC' time example given on http://en.wikipedia.org/wiki/Unix_time instead of starting with a wrong example.
2 个评论
Dan
2012-8-12
Current Wikipedia time is
1344541161 (2012-08-09 19:39:21Z)
>> utc = 1344541161
utc =
1.3445e+09
>> datestr(datenum([1970, 1, 1, 0, 0, utc]))
ans =
09-Aug-2012 19:39:21
I just blew everyone's mind...
marleen_ade
2018-7-27
perfect! Leave out the square brackets, and it works here too (R2015a 32 bit)
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