Summation with FOR Loop

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Me29
Me29 2017-4-17
评论： Cameron Cooke 2021-10-19
Hello, Super noob question, but how do I do the attached picture in MatLab using a FOR loop. I just need to know how to set up the loop, not the actual values. Thanks for any help!

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采纳的回答

Torsten
Torsten 2017-4-18
omega=...;
t=...;
N=...;
summe = 0.0;
for k=1:N
summe = summe + sin(omega*t*(2*k-1))/(2*k-1);
end
Best wishes
Torsten.
  2 个评论
Me29
Me29 2017-4-18
I don't think that is correct.. Given t=0:20, N=1000, omega=1, it should look like a square wave. The function basically sums a series of sine functions and approximates a square wave. Using your code, it doesn't do that... Any other ideas? Thanks!
Torsten
Torsten 2017-4-19
Try
t=0:2/pi/100:2/pi
omega=1;
N=1000;
summe = 0.0;
for k=1:N
summe = summe + sin(omega*t*(2*k-1))/(2*k-1);
end
plot(t,4/pi*summe)
Best wishes
Torsten.

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更多回答（3 个）

Jan
Jan 2017-4-17
You cannot run a loop from 1 to infinity in Matlab. Either solve the summation symbolically or find out, if this sum converges and you can use a certain number of elements to get the result with a wanted accuracy.
  1 个评论
Me29
Me29 2017-4-17
Sorry failed to mention, assume the limit of the summation is a real value input from the user. I just need the setup for the FOR loop.

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Arzu Ahmadova
Arzu Ahmadova 2019-5-22
Hi,
Could you explain please how to code more than 2 different inifinite sums in loop?
daniel domshlak
daniel domshlak 2020-3-29
i=0;
x = input ('choose the initial value : ');
y = input ('choose final value : ');
n=(x:y);
summe=0;
for i=x:y
a=(i*2+1).^3;
summe = summe + a;
end
summe
  3 个评论
显示 1更早的评论
daniel domshlak
daniel domshlak 2020-3-29
if someone finds a way to shorten this, don't hassitate to sahare.

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