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I created a zeros (n+1 by n+1) matrix. And I want the value 2*i on the row (2 : n)&(column 1:n-1) , where i is from 1 to n-1, how should I get that? Can anyone help me out?

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kingsley
kingsley 2017-4-19
编辑： kingsley 2017-4-19
I tried this :
n=4;
A=zeros(n+1);
for i=2:n-1
A([2:n,2:n-1])=[2*i]
end
But it didnt work

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2017-4-19
n = 4;
A = zeros(n);
A(2:n+1:end) = 2*(1:n-1);
A(n+1,n+1) = 0;

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KSSV
KSSV 2017-4-19
n = 4 ;
A = zeros(n+1) ;
A(2:n,1:n-1) = repmat(2*(1:n-1),n-1,1) ;
  1 个评论
kingsley
kingsley 2017-4-19
编辑：kingsley 2017-4-19
Hi, KSSV. First of all, thanks for your effort! I might not be very clear on the requirement of the matrix. The attachment is the required matrix I need to make. And the xi is from 1 to n-1 Thanks !!!!

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